Answer:
Step-by-step explanation:
If the area of a triangle is 150cm^2, the formula would look like:
150=0.5b*h
So, if we were to solve for the base in terms of h, we'd simply divide both sides by 0.5b getting:
(150)/(0.5b)=h
which simplifies to
h=300b
A=πr²
pool=π(y-4)²=π(y²-8y+16)
total=π(y+4)²=π(y²+8y+16)
walkway=total-pool
walkway=π(y²+8y+16)-π(y²-8y+16)=
π(y²+8y+16-y²+8y-16)=
π(16y)=
16πy
first option is answer
Answer:
y = (x - 3)² - 4 Vertex form
(3, -4) Vertex
Step-by-step explanation:
f(x) = x² - 6x + 5
Complete the square
y = (x - 3)² + 5 - (-3)²
y = (x - 3)² + 5 - 9
y = (x - 3)² - 4 Vertex form
(3, -4) Vertex
r
sin
θ
=
−
3
Explanation:
Imagine we have a point
P
with Rectangular (also called Cartesian) coordinates
(
x
,
y
)
and Polar coordinates
(
r
,
θ
)
.
The following diagram will help us visualise the situation better:
https://keisan.casio.com/exec/system/1223526375
https://keisan.casio.com/exec/system/1223526375
We can see that a right triangle is formed with sides
x
,
y
and
r
, as well as an angle
θ
.
We have to find the relation between the Cartesian and Polar coordinates, respectively.
By Pythagora's theorem, we get the result
r
2
=
x
2
+
y
2
The only properties we can say about
θ
are its trigonometric functions:
sin
θ
=
y
/
r
⇒
y
=
r
sin
θ
cos
θ
=
x
/
r
⇒
x
=
r
cos
θ
So we have the following relations:
⎧
⎪
⎨
⎪
⎩
r
2
=
x
2
+
y
2
y
=
r
sin
θ
x
=
r
cos
θ
Now, we can see that saying
y
=
−
3
in the Rectangular system is equivalent to say
r
sin
θ
=
−
3
Answer link
Jim G.
May 19, 2018
r
=
−
3
sin
θ
Explanation:
to convert from
cartesian to polar
∙
x
x
=
r
cos
θ
and
y
=
r
sin
θ
⇒
r
sin
θ
=
−
3
⇒
r
=
−
3
sin
θ
Answer:
The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only
Step-by-step explanation:
* Lets revise some facts about the quadrilateral
- Quadrilateral is a polygon of 4 sides
- The sum of measures of the interior angles of any quadrilateral is 360°
- The sum of measures of the exterior angles of any quadrilateral is 360°
* Lets solve the problem
- DEGC is a quadrilateral
∵ m∠BEG = (19x + 3)°
∵ m∠EGC = (m∠GCB + 4x)°
∵ The sum of the measures of its interior angles is 360°
∴ m∠BEG + m∠EGC + m∠GCB + m∠CBE = 360
∴ (19x + 3) + (m∠GCB + 4x) + m∠GCB + m∠CBE = 360 ⇒ add the like terms
∴ (19x + 4x) + (m∠GCB + m∠GCB) + m∠CBE + 3 = 360 ⇒ -3 from both sides
∴ 23x + 2m∠GCB + m∠CBE = 375
∵ The sum of measures of the exterior angles of any quadrilateral is 360°
∴ The statement in answer F is only true