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Alika [10]
3 years ago
5

Describe the set of all complex numbers that are at a distance of 2 units from the origin.

Mathematics
1 answer:
Andreyy893 years ago
8 0

Answer:

The description of the set is A = \{s\in \mathbb{C}|\|s\| = 2\}.

Step-by-step explanation:

From Complex Analysis, we remember that complex numbers are numbers whose form is:

s = a+i\, b, a,b \in \mathbb{R} (1)

Where i = \sqrt{-1}.

In addition, the distance from the origin is defined by the following Pythagorean identity:

\|s\| = \sqrt{a^{2}+b^{2}} (2)

The following condition must be satisfied:

\|s\| = 2

Then, the set of all complex numbers that are at a distance of 2 units from the origin is described below:

A = \{s\in \mathbb{C}|\|s\| = 2\} (3)

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Numbers that add to -0.5 and multiply to 1
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Short Answer
There are two numbers
x1 = -0.25 + 0.9682i   <<<< answer 1
x2 = - 0.25 - 0.9582i   <<<< answer 2 
 
I take it there are two such numbers.
Let one number = x
Let one number = y

x + y = -0.5    
y = - 0.5 - x       (1)
xy = 1               (2)

Put equation 1 into equation 2
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-0.5x - x^2 - 1 = 0          Order these by powers
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\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}

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\text{x = }\dfrac{ -0.5 \pm \sqrt{0.5^{2} - 4*1*1 } }{2*1}

x = [-0.5 +/- sqrt(0.25 - 4)] / 2
x = [-0.5 +/- sqrt(-3.75)] / 2
x = [-0.25 +/- 0.9682i

x1 = -0.25 + 0.9682 i
x2 = -0.25 - 0.9682 i

These two are conjugates. They will add  as x1 + x2 = -0.25 - 0.25 = - 0.50.

The complex parts cancel out.  Getting them to multiply to 1 will be a little more difficult. I'll do that under the check.

Check
(-0.25 - 0.9682i)(-0.25 + 0.9682i)
Use FOIL
F:-0.25 * -0.25 = 0.0625
O: -0.25*0.9682i
I: +0.25*0.9682i
L: -0.9682i*0.9682i = - 0.9375 i^2 = 0.9375

Notice
The two middle terms (labled "O" and "I" ) cancel out. They are of opposite signs.

The final result is 0.9375 and 0.0625 add up to 1
 
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