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d1i1m1o1n [39]
3 years ago
15

Help this is a hard question...

Mathematics
2 answers:
suter [353]3 years ago
8 0
I would be E and C
(If you want me to explain I can)

Hope this helps

Have a great day/night
Kay [80]3 years ago
8 0
C and E are the correct answers
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What is the median of 82, 4, 94, 4, 60, 91<br> And what is the mode and range
Dimas [21]

Answer:

The median is 55.833

The range is 90

The mode is 4

Step-by-step explanation:

To find median you

1. Arrange your numbers in numerical order.

2. Count how many numbers you have.

3. If you have an odd number, divide by 2 and round up to get the position of the median number.

4.If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

To find mode you put the numbers in order from least to greatest and count how many times each number occurs. The number that occurs the most is the mode.  To find range you first put all the numbers in order. Then subtract (take away) the lowest number from the highest. The answer gives you the range of the list.

4 0
3 years ago
You need a 45% alcohol solution. On hand, you have a 175 mL of a 25% alcohol mixture. You also have 70% alcohol mixture. How muc
Bezzdna [24]

175 mL at 25% concentration of alcohol contains 0.25 (175 mL) = 43.75 mL of alcohol. If <em>v</em> is the amount of the 70% solution that you use, then that amount contains 0.7<em>v</em> mL of alcohol.

Mixing these two yields a total volume of 175 mL + <em>v</em>, and it contains 43.75 mL + 0.7<em>v</em> alcohol. You want to end up with a concentration of 45%, which means the ratio of the amount of alcohol to the total volume needs to be 0.45:

(43.75 mL + 0.7<em>v</em>) / (175 mL + <em>v</em>) = 0.45

Solve for <em>v</em> :

43.75 mL + 0.7<em>v</em> = 0.45 (175 mL + <em>v</em>)

43.75 mL + 0.7<em>v</em> = 78.75 mL + 0.45<em>v</em>

0.25<em>v</em> = 35 mL

<em>v</em> = 140 mL

5 0
3 years ago
The equation $a^7xy-a^6y-a^5x=a^4(b^4-1)$ is equivalent to the equation $(a^mx-a^n)(a^py-a^2)=a^4b^4$ for some integers $m$, $n$
Ksivusya [100]
Let <span>simplify the equations a^7xy-a^6y-a^5x=a^4(b^4-1) and (a^mx-a^n)(a^py-a^2)=a^4b^4:
</span>
<span>1) a^7xy-a^6y-a^5x+a^4=a^4b^4
</span>
<span>and
</span>
<span>2) a^{m+p}xy-a^{n+p}y-a^{m+2}x+a^{n+2}=a^4b^4.
</span>
<span>Equate the coefficients:
</span><span>
</span><span>xy: m+p=7  \\ y: n+p=6 \\ x:  m+2=5 \\ 1: n+2=4.</span>
Then n=2 \\ p=4 \\ m=3 and mnp=24.
<span />
3 0
3 years ago
Please help this hurts
Svetllana [295]

Answer:

6x - 11y = -13 is the answer.

Step-by-step explanation:

Let's plug in the points to see what sticks.

Start with (-4, -1)

1) 11x - 6y = 11(-4) - 6(-1) = -44 + 6 = -38 \neq 13

2) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13

3) 6x - 7y = 6(-4) - 7(-1) = -24 + 7 = -17 \neq 17

4) 6x - 11y = 6(-4) - 11(-1) = -24 + 11 = -13 \neq 13

The only one that fits is #2.  Let's try the other point to be sure.

2) 6x - 11y = 6(1.5) - 11(2) = 9 - 22 = -13

3 0
3 years ago
PLEASE HELP I NEED THIS TURNED IN,
DerKrebs [107]

Answer:

3/3 is equivilant to 1.

Multiplying 6/4 by 1, would be 6/4. Also, multiplying 6/4 by 3/3 would be 18/12, which could be simplified to 6/4.

Hope this helps!    

3 0
3 years ago
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