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3 years ago

How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?

Mathematics

2 answers:

stepladder [879]3 years ago

3 0

None i hope it helped

Korolek [52]3 years ago

3 0

Answer:

He or she is correct i just did the test and it is none tell me if you want all the questions and all the answers by

Step-by-step explanation:

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Which expression will result in the LCM of 6 and 8?<br><br> I LOVE LIL BUB \sheis a cat

Klio2033 [76]

Answer:

Step-by-step explanation:

6x4=24 and 8x3=24

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Keona pours 128 ounces of water into a jar 3 times to fill it. How many pints of water does it take to fill the jar? (4 points)

soldier1979 [14.2K]

Answer:

24 pints

Step-by-step explanation:

128 ounces · 3 = 384 ounces

384/16 = 24 pints

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7^8 x 7^3 x 7^4 divided by 7^9 x 7^5 ASAP answer please and thankyou

sergeinik [125]

Answer:

$\huge\underline\color{purple}{Answer ☘}$

$7 {}^{8} \times 7 {}^{3} \times 7 {}^{4} \div 7 {}^{9} \times 7 {}^{5} \\ = > 7 {}^{8 + 3 + 4 - 9 + 5 } \\ = > 7 {}^{11}$

<h3>furthєr... </h3>

$\color{pink}\boxed{Additional \: \: Information♡}$

$properties \: that \: we \: used \: while \\ solving \: the \: question \: are \: as \: follows - \\ \\ x {}^{m} \times x {}^{n} = x {}^{m + n} \\ \frac{x {}^{m} }{x {}^{n} } = x {}^{m - n}$

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2 years ago

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14. Peter needs to buy a package of pencils to write his final exam. The store offers two packages.

miskamm [114]

Answer:

Step-by-step explanation:

peter can buy pack of nine pencils

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9 divided by 2.34=3.8

package 2 is just 0.3 more

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3 years ago

Which expression is equivalent to sqrt8x^7y^8? assume x>0

Ilia_Sergeevich [38]

Answer:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

Step-by-step explanation:

Given

$\sqrt{8x^7y^8$

Required

Evaluate

$\sqrt{8x^7y^8$

Separate each factor with multiplication sign

$\sqrt{8*x^7*y^8$

Express 8 as 4 * 2 and $x^7$ as $x^6 * x$

$\sqrt{4 * 2 *x^6 * x*y^8$

Split each factor

$\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Evaluate $\sqrt4$

$2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}$

Apply law of indices:

$2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}$

$2 * \sqrt{2} * x^3 * \sqrt{x} * y^4$

Reorder

$2* x^3 * y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2} * \sqrt{x}$

$2x^3y^4 * \sqrt{2*x}$

$2x^3y^4 * \sqrt{2x}$

$2x^3y^4 \sqrt {2x$

Hence:

$\sqrt{8x^7y^8$ $= 2x^3y^4 * \sqrt{2x}$

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3 years ago

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