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Softa [21]
3 years ago
12

Let’s think about another type of scenario. What if you were told that a bracelet requires 10 beads and 10 minutes to make while

a necklace requires 20 beads and takes 40 minutes to make. The craftsman has 1000 beads to work with and he has 1600 minutes in which to work. If a bracelet costs $5 and a necklace costs $7.50, what is the maximum revenue that the craftsman can take in?
There are four inequalities in this situation. Let b be the number of bracelets made and n be the number of necklaces made. The system of inequalities for this situation is:
Mathematics
1 answer:
Savatey [412]3 years ago
7 0

Hi, your question appears to be unclear. However, I inferred this to be a linear programming problem.

Answer:

<u>$500</u>

Step-by-step explanation:

To begin we need to state the system of inequalities for this situation (constraints):

  • For the number of available beads:  10b + 20n  \leq 1000 where b represents the number of bracelets made, and n represents the number of necklaces made.
  • For the available time to make the jewelry: 10b+40n\leq 1600
  • b\geq 0
  • n\geq 0

From the question, we note we are required to find the maximum revenue that the craftsman can take in. In other words, the optimization equation is 5b+7.5n = maximum revenue (taking note that a bracelet costs $5 and a necklace costs $7.50)

Next, we are to plot the inequalities on a graph to determine the feasible region: Doing so should give us these main vertices: (0,0) (0,40) (40,30 (100,0).

By substituting the vertices into the optimization equation (replacing b, and n) we can determine which quantity gives the maximum revenue:

For (0,40) ⇒ 5(0) + 7.5(0) = $0

For (0,40) ⇒ 5(0) + 7.5 (40) = $300

For (40, 30) ⇒ 5(40) + 7.5 (30) = $425

For (100, 0) ⇒ 5(100)+7.50(0) = $500

We notice that at point  (100, 0) we have a maximum revenue of $500.

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Pls helppppp! I'll give brainliest :))<br><br> 1/3y+6-2/3y
Vitek1552 [10]

Answer: 5.66666666667

Step-by-step explanation: Thanks and have a Savage day.

5 0
3 years ago
How are the functions f(x)=16^x and g(x)=16^(1/2)x related? The output values of g(x) are one-half the output values of f(x) for
Goshia [24]
F(x) =16ˣ     and   g(x) = 16⁽ˣ/₂⁾

Since 16 = 2⁴, then we can write:

f(x) =2⁽⁴ˣ⁾  and  g(x) = 2⁽⁴ˣ/₂⁾ = 2²ˣ

for x = 1 f(x) =  2⁴ = 16
for x = 1 g(x) = 2² = 4
(√16 = 4)

for x = 2 f(x) =  2⁸ = 256
for x = 2 g(x) = 2⁴ =16
(√256) = 16

for x = 3 f(x) =  2¹² = 4096
for x = 1 g(x) = 2⁶ =  64
(√4096 = 64)

We notice that:
The output values of g(x) are the square root of the output values of f(x) for the same value of x.
 
6 0
3 years ago
Read 2 more answers
What is the answer for 2(a+b)=
Rainbow [258]
<h3>It is equivalent to 2a+2b</h3>

We use the distributive property.

Multiply the outer term 2 by each term inside ('a' and b)

2 times a = 2a

2 times b = 2b

We add those results to get 2a+2b. We cannot combine these terms as they are not like terms.

8 0
3 years ago
18x26=? I don't get how to do this
elena-s [515]

Answer:

468

Step-by-step explanation:

Set it up like the following-

18

26

--------

108

360

--------

408

Take the right number (6) and multiply it with 18

6 x 18 = 108

Now do the same with 2, except put a 0 at the end

2 x 18 = 36

add 0

360

Add both numbers-

360 + 108 = 468

6 0
3 years ago
Determine the length and midpoint of the segment whose endpoints are (–15, 9) and (–4, 11).
ch4aika [34]
(-15,9) \\&#10;x_1=-15 \\&#10;y_1=9 \\ \\&#10;(-4,11) \\&#10;x_2=-4 \\&#10;y_2=11 \\ \\&#10;\hbox{the length:} \\&#10;l=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}=\sqrt{(-4+15)^2+(11-9)^2}=\\&#10;=\sqrt{11^2+2^2}=\sqrt{121+4}=\sqrt{125}=\sqrt{25 \times 5}=5\sqrt{5} \\ \\&#10;\hbox{the midpoint:} (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}) \\&#10;\frac{x_1+x_2}{2}=\frac{-15-4}{2}=\frac{-19}{2}=-9.5 \\&#10;\frac{y_1+y_2}{2}=\frac{9+11}{2}=\frac{20}{2}=10 \\&#10;(-9.5,10)

The length of the segment is 5√5, the midpoint of the segment is (-9.5,10).
6 0
3 years ago
Read 2 more answers
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