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Rufina [12.5K]
2 years ago
10

Fill in the blank.

Mathematics
2 answers:
Alex Ar [27]2 years ago
6 0

Answer:

(2m^2)^3=8m^6

Step-by-step explanation:

............

irinina [24]2 years ago
3 0
2m^2 is the answer
plug it in the question and you’ll get smth like this

(2m^2)^3 = 2^3m= 8m
(m^2)^3= m^6

(x^y)^z= x^y*z
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Gary is making a casserole but only needs 1/3 of the original serving size. If the number of servings Gary needs is 4, how many
Deffense [45]

Answer:

What equation will model the situation?

✔ x/3 = 4

How many servings did the original recipe make?

✔ 12

Step-by-step explanation:

Hope this helps!

7 0
3 years ago
Read 2 more answers
The answer to the question to my test
wel

Answer:

Option C, 262 cm^3

Step-by-step explanation:

<u>Step 1:  Substitute 5 for radius and 10 for height</u>

V = 1/3 * pi * r^2 * h

V = 1/3 * pi * (5)^2 * (10)

V = 1/3 * pi * 25 * 10

V = 250pi/3

V = 261.79

Answer:  Option C, 262 cm^3

7 0
3 years ago
AABC~ ADEF. What is the scale factor?<br><br> Help please
vladimir1956 [14]

Answer:

3:1 or 3

Step-by-step explanation:

the left triangle is scaling up to the right triangle. 5/15 is 1/3

7/21 is 1/3

4/14 is 1/3

since it is scaling UP, the scale factor is 3:1

7 0
3 years ago
Without solving, tell what is true of the product of 3 and 2/3 =?
Kisachek [45]

Answer:

3 is a whole number while 2/3 is less than 3

Step-by-step explanation:

5 0
3 years ago
To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

kx^2-5

so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

16k-5=-12+k

16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




7 0
3 years ago
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