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posledela
3 years ago
13

When the outlier are removed how does the mean change

Mathematics
1 answer:
Margaret [11]3 years ago
6 0
The mean increases when the outlier is removed
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The perimeter of a rectangular ink pad is 36 centimeters. The ink pad is 12 centimeters wide. How tall is it?
Nikitich [7]

Answer:

6 cm

Step-by-step explanation:

36-24=12 and 12/2 is 6

Hope this helps!!!!!!!!!!!!!!

3 0
3 years ago
Pharmacy Technician Rolando received a prescription for 150 calcium carbonate tablets for the patient. Rolando used 1/3 of the s
Feliz [49]
450

If he used 1/3 of the stock bottle, then you have
150=1/3x

Now, you multiply both sides by 3, which gives you

450=x

So, originally there were 450 bottles in the stock bottle
7 0
3 years ago
Y^2+11y+18=0<br><br> solve using quadratic formula<br><br> help!!
AlexFokin [52]

Answer:

y = -2, -9

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
NEEDs HELP<br><br> AB ⊥ AC<br><br> true or false<br> idk i think it's false
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Perpendicular means the slopes are opposite inverse of each other
If line a is slope 2, the perpendicular line to Line a would have a slope - 1/2
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4 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
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