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Hitman42 [59]
3 years ago
13

Y=4x-2y and y=x+3 estimate the solutions to the systems of equations

Mathematics
1 answer:
polet [3.4K]3 years ago
6 0

Answer:

3y=4x

y=4x/3

4x/3=x+3

x/3=3

X=9

y=12

(9,12) this is the answer

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Nezavi [6.7K]

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3.72 x 100000000= 372000000

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the system of equatuions 2y = 14 - 2x and y= -x+7 is graphed. what is the solution to the system of equations
Alex73 [517]

Answer:

the solution is the whole line y = -x + 7

Step-by-step explanation:

both equations are identical

2y = 14 - 2x

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which is exactly the same information as y=-x+7

so, there is no single crossing point. they are exactly covering each other. what "remains" is simply the whole line.

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3 years ago
Find the area of the trapezoid. Pls explain and I will mark brainliest.
timama [110]

Answer:

  • B. 191.4 m²

Step-by-step explanation:

Split the trapezoid as pictured below

Find its height and the upper base, then find the area of the trapezoid.

There are 3 pieces, two of them are 45°×45° and 30°×60°×90° triangles

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<u>The above mentioned properties give us:</u>

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8 0
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Describe how you regroup when you find the sum of 64+43
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When adding two digit numbers u will be looking at the ones and deciding if they can regroup them for a ten. You might want to equate regrouping with trading a term that you will understand immediately you will begin to add 2 digit numbers by using ten and ones blocks. And the answer is (107)
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A right triangle has one vertex on the graph of y = 9 - x^2 , x &gt; 0, at ( x , y ), another at the origin, and the third on th
jenyasd209 [6]

Answer:

  a.  A(x) = (1/2)x(9 -x^2)

  b.  x > 0 . . . or . . . 0 < x < 3 (see below)

  c.  A(2) = 5

  d.  x = √3; A(√3) = 3√3

Step-by-step explanation:

a. The area is computed in the usual way, as half the product of the base and height of the triangle. Here, the base is x, and the height is y, so the area is ...

  A(x) = (1/2)(x)(y)

  A(x) = (1/2)(x)(9-x^2)

__

b. The problem statement defines two of the triangle vertices only for x > 0. However, we note that for x > 3, the y-coordinate of one of the vertices is negative. Straightforward application of the area formula in Part A will result in negative areas for x > 3, so a reasonable domain might be (0, 3).

On the other hand, the geometrical concept of a line segment and of a triangle does not admit negative line lengths. Hence the area for a triangle with its vertex below the x-axis (green in the figure) will also be considered to be positive. In that event, the domain of A(x) = (1/2)(x)|9 -x^2| will be (0, ∞).

__

c. A(2) = (1/2)(2)(9 -2^2) = 5

The area is 5 when x=2.

__

d. On the interval (0, 3), the value of x that maximizes area is x=√3. If we consider the domain to be all positive real numbers, then there is no maximum area (blue dashed curve on the graph).

5 0
3 years ago
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