I don't know the answer choices but the inverse is F(x)=-x-13.
15=|2x-3|
then you take the absolute value sign away
(1) 15=2x-3
and
(2) -15=2x-3
you have a negative 15 because it is the absolute value then you solve for both equations
and get
(1) x= 9
(2) x= -6
I don't really get what this means, but I would say 12 can be represented by 4*3, 12*1, 2*6, twelve, and it could also be represented by something like 60/5, or 24-12, etc. Like I said, I'm not so sure about what this is asking.
Answer:
![\sqrt{8 m^{6} n^{3}}](https://tex.z-dn.net/?f=%5Csqrt%7B8%20m%5E%7B6%7D%20n%5E%7B3%7D%7D)
Step-by-step explanation:
<span>Part A: Find (h + t)(x). Show your work.
</span><span>h(x) = 5x − 2 and t(x) = 4x + 6
</span><span>so
</span>(h + t)(x) = 5x − 2 + 4x + 6
(h + t)(x) = 9x +4<span>
Part B: Find (h ⋅ t)(x). Show your work.
</span>h(x) = 5x − 2 and t(x) = 4x + 6
so
(h ⋅ t)(x) = (5x − 2) (4x + 6)
(h ⋅ t)(x) = 20x^2 + 30x - 8x - 12
(h ⋅ t)(x) = 20x^2 + 22x - 12<span>
Part C: Find h[t(x)]. Show your work.
</span>h(x) = 5x − 2 and t(x) = 4x + 6
so
h[t(x)] = 5(4x + 6) − 2
h[t(x)] = 20x + 30 - 2
h[t(x)] = 20x + 28
hope all help.