The sum of five consecutive positive integers is 2020. Find the largets of these numbers.

Mathematics

1 answer:

Vinil7 [7]2 years ago

3 0

The largest integers of the numbers is 406.

<h3>How to find the five consecutive positive integers?</h3>

The sum of five consecutive positive integers is 2020.

Therefore,

let

the first positive integer = x

Hence,

x + x + 1 + x + 2 + x + 3 + x + 4 = 2020

5x + 10 = 2020

5x = 2020 - 10

5x = 2010

x = 2010 / 5

x = 402

largest integer = 402 + 4 = 406

Therefore, the largest integers of the numbers is 406.

learn more on integers here: brainly.com/question/15292688?

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