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Paraphin [41]
3 years ago
6

How to calculate a 15% tip?

Mathematics
2 answers:
MrRa [10]3 years ago
8 0
If you want to leave a 15% tip, use the fact that 15% = 10% + 5%. Calculate 10% of the bill by moving the decimal point one position to the left. Then, take that number, divide it in half, and add the new amount to the original 10%
Vikki [24]3 years ago
8 0
Hi I need help with my work can you help me please
You might be interested in
Alberto has 2 cats the smaller cat weighs 10 3/4 pounds the larger cat weighs 15 1/3 pounds how much do the cats weigh altogethe
ElenaW [278]

Answer:

A. 26 1/2

Step-by-step explanation:

change denominator so they can be the same

3/4*3  =   9/12

1/3*4   =   4/12

Add the whole numbers : 10 +15=25

9/12+4/12= 13/12 so 1 1/12

26 1/12

4 0
3 years ago
Find F of G of X where f of x equals 9 over X and G of x equals x over x + 1​
Sergeu [11.5K]
Sorry I can’t answer this right now but I’ll will answer later
8 0
3 years ago
Which relation is a function?
Veseljchak [2.6K]

Answer: B


Step-by-step explanation:

because in A it says 2=3 and 2=2 that is not a function each number has to have an outcome of one possible answer if that is true it is a function.

7 0
4 years ago
Two times the sum of a number and 4 is 9.
OleMash [197]

Answer:

2(x+4)

Step-by-step explanation:

6 0
3 years ago
Please could u help me with this <br> Thank u sooo much:)
Simora [160]
Ok so the spread can be given by the range, interquartile range and standard deviation in this case.
Gretchen's data: Range = 22 - 3 = 19, IQR = 5, Sx = 4.69
Manuel's data: Range = 14 - 3 = 11, IQR = 4, Sx = 3.14

1. Gretchen's data is more spread out than Manuel's, which is primarily displayed by the much larger range and standard deviation for Gretchen's data (range = 19, standard deviation = 4.69) compared to Manuel's data (range = 11, standard deviation = 3.14). The interquartile range of both data sets are almost equal however, with the IQR of Gretchen's data equal to 5 and that of Manuel's data equal to 4, which may show that the greater spread of Gretchen's data is affected by the larger values in his data, namely the outlier at 22.

2. Gretchen's data set with outlier removed:
Mean = 8.71
Median = 8.5
Standard deviation = 3.31
Interquartile range = 3

3. Removing the outlier moved the centre closer, with the mean now at 8.71 and median at 8.5, compared to Manuel's data's mean of 8 and median of 8. The spread was also closer to Manuel's, with the standard deviation now equal to 3.31 (Manuel's data's standard deviation = 3.14) and the range now equal to 12 (compared to Manuel's data's range of 11). The IQR range did change from 5 to 3 after removing the outlier but there is still a difference of 1 between the IQR of Gretchen's data and that of Manuel's data. Overall however, both the centre and spread moved closer to that of Manuel's data after removing the outlier.
7 0
4 years ago
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