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3 years ago

Find the area of the shaded sector. Round to the nearest tenth. Please help.

Mathematics

1 answer:

Maslowich3 years ago

5 0

The formula for area of a sector is...

A = $\frac{1}{2} r^{2}$ θ

NOTE θ is converted from degree to radian

θ = 167 × $\frac{\pi }{180}$

θ = $\frac{167\pi }{180}$

so...

A = $\frac{1}{2}(17.8)^{2} (\frac{167\pi }{180})$

A = (1/2)(316.84)(2.9146)

A = 158.42 * 2.9146

A = 461.7

Hope this helped!

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A 12 sided number cube with the numbers 1 through 12 is rolled.Select from the drop down menu to correctly complete the statemen

ioda

The 12 sided cube with the numbers 1 to 12 is rolled. That means it can land on any number from 1 to 12. The number of total possible outcomes is 12. The number of favourable outcomes, that is, the number of times the cube lands on a number than 4 is 12-1=11.
Probability=Number of favourable outcomes/number of total possible outcomes
= 11/12
= 0.92
I really hope this helps! And pls mark it as brainliest.

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3 years ago

Parcc chapter 7 pythagorean theorem

Bumek [7]

So, we know that a^2 + b^2 = c^2. Right? That is called the Pythagorean Theorem.

In this case. We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b. a & b are just the two legs of the right triangle.

So, if we say that 39 is a, 40 is b, and x is c. We can plug it into the Pythagorean Theorem.

39^2 + 40^2 = x^2

I'll let you take it from there.

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3 years ago

HELP!!!! Solve for y in the following equation: -4y + 9 = -28

Flura [38]

Answer:

y = 37/4

Step-by-step explanation:

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3 years ago

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Find the missing geometric means in this sequence.

amid [387]

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3 years ago

You recently took a statistics exam in a large class. The instructor tells the class that the scores were Normally distributed,

Lunna [17]

Answer:

b. the area to the right of 2

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.

In this problem:

$X = 96, \mu = 72, \sigma = 12$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{96 - 72}{12}$

$Z = 2$

Percentage who did better:

P(Z > 2), which is the area to the right of 2.

5 0

3 years ago