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Korvikt [17]
3 years ago
11

Suppose commute times in a large city are normally distributed and that 63.70% of commuters in this city take more than 22 minut

es to commute one-way. If the standard deviation of such commutes is 6.3 minutes, what is the mean commute?
Mathematics
1 answer:
USPshnik [31]3 years ago
6 0

Answer:

The mean is 24.205

Step-by-step explanation:

Firstly, we need to get the z-score

From the question, the probability we have is the probability that commuters take more than 22 minutes to commute one-way

So the probability we had was;

P( x > 22)

So we need the z-score corresponding to 63.70% or simply 0.637

We can use the standard normal distribution table to get this

Mathematically, from the standard normal distribution table this is -0.35

z-score = (x- mean)/SD

-0.35 = (22-mean)/6.3

22-mean = -2.205

mean = 22 + 2.205 = 24.205

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3 years ago
Read 2 more answers
Rewrite the function by completing the square <br> f(x)=x^2-14x+63
Veseljchak [2.6K]

Answer:

f(x) = (x - 7)² - 14

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Equality Properties

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Vertex Form: f(x) = a(bx - c)² + d
  • Completing the Square: (b/2)²

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 14x + 63

<u>Step 2: Rewrite</u>

  1. Separate:                              f(x) = (x² - 14x) + 63
  2. Complete the Square:         f(x) = (x² - 14x + 49) + 63 - 49
  3. Simplify:                                f(x) = (x - 7)² - 14
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3 years ago
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