Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
Answer:
A'(5,-11)
Step-by-step explanation:
Your only changing the y if you are reflecting over the x-axis but change the x if you are reflecting over the y-axis.
<span>9 - 3x - (-8y) + 9x -y
9 - 3x + 8y + 9x - y
9 - 3x + 9x + 8y - y
9 + 6x + 7y</span>
because in trigonometric form, the argument can take on multiple values due to the nature of trigonometry
for example, we have coterminal angles.
sin(30) + cos(30) is the same as sin(30+360n) + cos(30+360n), where n is an integer.
