Answer:
6,I can't help with the second one I wasn't good with that parallel lines
Step-by-step explanation:
Y2-Y1. So 3-9. 6
--------- - - -- = - - =6
X2-X1. 1-2. 1
If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).
Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).
If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.
• Case 1: suppose <em>x</em> < 0. Then
<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = -1/√2 → <em>y</em> = ±1/√2
• Case 2: suppose <em>x</em> ≥ 0. Then
<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)
<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0 → <em>x</em> = 1/√2 → <em>y</em> = ±1/√2
In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.
We have the following function that is a
quadratic function:
So the graph of this function is shown in the figure below. This is a <em>parabola</em> as you can see. The roots of this functions, that is, the x-intercepts are:
As you can see in the figure. This function decreases from
and increases from
Finally, another thing we can see from the graph is that the vertex is the point:
Yes, It is reasonable. I think this because you are dealing with 60 blocks, and out of every 5 blocks there are 3 red. 5 goes into 60 12 times. 3 multiplied by 12 is 36. 36 is more than 32. So, I think that it is reasonable. If this explanation didn't make sense, then feel free to ask for more. I hope this helped!
It is already simplified because 18 cant go into 25
