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lyudmila [28]
3 years ago
6

Interest calculated only on the principle is

Mathematics
1 answer:
Reptile [31]3 years ago
7 0
Amount of a loan or deposit ?
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A principal of $3800 is invested at 3.75% Interest, compounded annually. How much will the investment be worth after 6 years?
IgorLugansk [536]

Answer:

Step-by-step explanation:

Simple interest formula: i = prt

i = interest

p = principle amount

r = rate

t = time (in years)

Substitute the numbers given in the problem.

i = $3800x0.0375x6

i = $855

In order to find the total investment, add the interest ($855) to the principle amount ($8500)

$855 + $8500 = $9355

If you need more help in this problem, please comment down below.

5 0
3 years ago
The answer please..:.....
Ivenika [448]

Answer:

566

Step-by-step explanation:

3 0
3 years ago
Simplify 2X^3- 3x^2- 5x +3 / x+ 1
Maslowich

Answer:

-6x+3÷x+1

Step-by-step explanation:

2x^3-3x^2-5x+3÷x+1

2x ×2x ×2x-3x +3x-5x+3÷x+1

8x-9x-5x+3÷x+1

8x-14x+3÷x+1

-6x+3÷x+1


6 0
4 years ago
Given segments AB and CD intersect at E.
nata0808 [166]

The length of a segment is the distance between its endpoints.

  • \mathbf{AB = 3\sqrt{2}}
  • AB and CD are not congruent
  • AB does not bisect CD
  • CD does not bisect AB

<u>(a) Length of AB</u>

We have:

\mathbf{A = (1,2)}

\mathbf{B = (4,5)}

The length of AB is calculated using the following distance formula

\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

So, we have:

\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}

\mathbf{AB = \sqrt{18}}

Simplify

\mathbf{AB = 3\sqrt{2}}

<u>(b) Are AB and CD congruent</u>

First, we calculate the length of CD using:

\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

Where:

\mathbf{C = (2, 4)}

\mathbf{D = (2, 1)}

So, we have:

\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}

\mathbf{CD = \sqrt{9}}

\mathbf{CD = 3}

By comparison

\mathbf{CD \ne AB}

Hence, AB and CD are not congruent

<u>(c) AB bisects CD or not?</u>

If AB bisects CD, then:

\mathbf{AB = \frac 12 \times CD}

The above equation is not true, because:

\mathbf{3\sqrt 2 \ne \frac 12 \times 3}

Hence, AB does not bisect CD

<u>(d) CD bisects AB or not?</u>

If CD bisects AB, then:

\mathbf{CD = \frac 12 \times AB}

The above equation is not true, because:

\mathbf{3 \ne \frac 12 \times 3\sqrt 2}

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0
3 years ago
El cubo de cuatro veces y​
olganol [36]

Answer:

????? what?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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