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3 years ago

Marshall has $0.34 in dimes and pennies. He has 7 coins altogether. How many coins of each kind does he have?

Mathematics

1 answer:

Grace [21]3 years ago

4 0

Dimes are 0.10 each

Pennies are 0.01 each

You need 4 pennies to get the 0.04

Then you would have 3 dimes .

3 x 0.10 = 0.30

4 x 0.01 = 0.04

0.30 + 0.04 = 0.34

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I would estimate the numbers as 700 and 40,000

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4 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

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4 years ago

Solve each system of liner equations y=2x+1 x+2y=17 pls help!

GalinKa [24]

Plug y=2x+1 into x+2y=17, we have:
x+ 2(2x+1)= 17
⇒ x+ 2*2x+ 2*1= 17 (distributive property)
⇒ x+ 4x+ 2= 17
⇒ 5x= 17-2
⇒ 5x= 15
⇒ x= 15/5
⇒ x= 3

y= 2x+1= 2*3+1= 7

Final answer: x= 3, y= 7~

3 0

4 years ago