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brilliants [131]

4 years ago

13

Select all of the following that are quadratic equations.

1 answer:

kifflom [539]4 years ago

5 0

A quadratic equation is one in which the highest exponent of x is 2.
$7x^2+14x=0$ is quadratic; the highest exponent is 2.
x³-3x²+1=0 is NOT quadratic. The highest exponent of x is 3, not 2.
5x-7=0 is NOT quadratic. The highest exponent of x is 1, not 2.
x²+3x-5=0 is quadratic; the highest exponent of x is 2.
x-5=9x+7 is NOT quadratic. The highest exponent of x is 1, not 2.
x²-x=3x+7 is quadratic; the highest exponent of x is 2.

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A real estate company is interested in the ages of home buyers. They examined the ages of thousands of home buyers and found tha

egoroff_w [7]

Answer:

Between 21 years and 75 years

Step-by-step explanation:

Given that a real estate company is interested in the ages of home buyers. They examined the ages of thousands of home buyers and found that the mean age was 48 years old, with a standard deviation of 9 years.

X the ages of home buyers is N(48, 9)

a) $30\leq x\leq 66\\|x-48|\leq 18\\|x-48|\leq 2\sigma$

Hence using Cheby chev inequality

$P(|x-48|\leq 2\sigma)\geq 1-\frac{1}{2^2} \\=0.75$

b) $25.5\leq x\leq 70.5\\|x-48|\leq 22.5\\|x-48|\leq 1.5\sigma$

$P(|x-48|\leq 1.5\sigma)\geq 1-\frac{1}{1.5^2} \\=0.556$

c) Using normal distribution we have

$P(|x-48|\leq 2\sigma)=0.95$

d) z value is 2.97

Hence x lies between

$(48-9*2.97, 49+9*2.97)\\=(21.27,74.73)$

Between 21 years and 75 years

4 0

3 years ago

A mail order company sells boxes of fishing lures for $26.95 per box. A charge of $8.95 is added to orders, regardless of the or

nikdorinn [45]

Answer:

y = 26.95x + 8.95

Step-by-step explanation:

26.95x, where x is the number of boxes, will represent the cost from the boxes ordered.

Since there is a $8.95 extra charge, this has to be added to 26.95x

So, the equation will be y = 26.95x + 8.95, where y is the total cost of the order and x is the number of boxes ordered

4 0

4 years ago

Which is different?

Alja [10]

A) Solve 3x+6y=24 for x.

Subtracting 6y from both sides, we get

3x+6y-6y=24-6y

3x = -6y+24

Dividing both sides by 3, we get

$\frac{3x}{3} = \frac{-6y}{3} +\frac{24}{3}$

x= -2y + 8

b) Solve 24−3x=6y for x.

Subtracting 24 from both sides, we get

24-24−3x=6y-24

-3x = 6y -24.

Dividing both sides by -3, we get

$\frac{-3x}{-3} =\frac{6y}{-3} -\frac{24}{-3}$

x= -2y + 8.

c) Solve 6y=24−3x for y in terms of x.

Dividing both side by 6.

$\frac{6y}{6} =\frac{24}{6}- \frac{3x}{6}$

y= $-\frac{1}{2}x+4$

d) Solve 24−6y=3x for x in terms of y.

Dividing both sides by 3, we get

$\frac{24}{3} - \frac{6y}{3} = \frac{3x}{3}$

8 - 2y = x.

x = -2y +8

<h3>Therefore, x=-2x+8 and $y=-\frac{1}{2}x+4.$ </h3>

7 0

3 years ago

Algebra 1: Equation or Inequality

baherus [9]

10.6 Months, so yeaa 10

5 0

3 years ago

Alex asked her friend Beau to bring his robots to the fair. Guests can buy tickets to play with the robots. Beau needs to rope o

andrey2020 [161]

Answer:

haha

Step-by-step explanation:

;ouhkiygluy

4 0

3 years ago