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brilliants [131]
3 years ago
13

Select all of the following that are quadratic equations.

Mathematics
1 answer:
kifflom [539]3 years ago
5 0
A quadratic equation is one in which the highest exponent of x is 2.
7x^2+14x=0 is quadratic; the highest exponent is 2.
x³-3x²+1=0 is NOT quadratic.  The highest exponent of x is 3, not 2.
5x-7=0 is NOT quadratic.  The highest exponent of x is 1, not 2.
x²+3x-5=0 is quadratic; the highest exponent of x is 2.
x-5=9x+7 is NOT quadratic.  The highest exponent of x is 1, not 2.
x²-x=3x+7 is quadratic; the highest exponent of x is 2.
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A test of abstract reasoning is given to a random sample of students before and after they completed a formal logic course. The
Natasha_Volkova [10]

Answer:

The right answer is "0.2".

Step-by-step explanation:

The given values are:

\bar{x_0} = 3.7

s_o=4.95

t_{\frac{0.05}{2} }=2.2621

As we know,

95% confidence for \mu_0 will be:

= \bar{x_0} \pm t_{\frac{0.05}{2} },n-1\times \frac{s_o}{\sqrt{n} }

The lower bound will be:

= 3.7-2.2621\times \frac{4.95}{\sqrt{10} }

= 0.16\simeq 0.2

The upper bound will be:

= 3.7+2.2621\times \frac{4.95}{\sqrt{10} }

= 7.23\simeq7.2

Thus the right answer is "0.2"

8 0
2 years ago
K/a = w - v, solve for a
erik [133]

Answer:

a=k-w+v

Step-by-step explanation:

k/a= w-v

a( k/a) = a (w-v)

k -w + v =a

4 0
3 years ago
Help please!!! Thank you
Elena L [17]

<u>Given</u>:

The given expression is \frac{4 d+28}{12 d+96} \cdot \frac{d^{2}+14 d+48}{d^{2}+9 d+14}

We need to multiply the terms.

<u>Multiplication of the terms:</u>

Before multiplying the terms, first we shall find the factors of the quadratic equations.

Thus, we have;

\frac{4 d+28}{12 d+96} \cdot \frac{(d+6)(d+8)}{(d+2)(d+7)}

Factor out the common terms, we get;

\frac{4 (d+7)}{12 (d+8)} \cdot \frac{(d+6)(d+8)}{(d+2)(d+7)}

Let us cancel the common terms from the above expression.

Thus, we have;

\frac{4 }{12 } \cdot \frac{(d+6)}{(d+2)}

Simplifying, the term, we get;

\frac{1}{3 } \cdot \frac{(d+6)}{(d+2)}

Now, we shall multiply the terms.

Hence, multiplying the terms, we get;

\frac{(d+6)}{3(d+2)}

Thus, the multiplied value of the given expression is \frac{(d+6)}{3(d+2)}

6 0
3 years ago
Write an equation for the following word sentence:<br><br> 16 is 8 more than a number.
Yuki888 [10]
x-\ number\\\\ 16=x+8\ \ \ | subtract\ 8\\\\&#10;x=16-8\\\\x=8\\\\ Number\ is \ equal\ to\ 8.
3 0
2 years ago
Read 2 more answers
Help, please someone
adell [148]

Answer:

what do you need help with?

7 0
3 years ago
Read 2 more answers
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