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daser333 [38]
3 years ago
8

Please help du tomorrow

Mathematics
1 answer:
Leokris [45]3 years ago
3 0
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².

To find the perimeter of each, we add the area of all sides.  For the first figure, the missing sides are 1 cm and 6 cm.  To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.

For the second figure, the missing sides are 4 cm and 3 cm.  To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.

For the third figure, the missing sides are 3 cm, 3 cm and 8 cm.  To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.

For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm.  To find the area, we have two squares whose dimensions are 10x10.

For the fifth figure, the missing sides are 3 cm and 9 cm.  To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
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8. In quadrilateral ABCD, AD is congruent to BC, and AD is parallel to BC. Andre has written a proof to show that ABCD is a para
luda_lava [24]

The correct choices to fill the blanks are listed below:

  1. AD
  2. BC
  3. AC
  4. CBA
  5. angle BAC
  6. CD

<h3>How to prove that a quadrilateral is a parallelogram</h3>

In this question we should fill the blanks based all information related to Euclidean geometry, especially concepts related to angles, triangles, parallelism and quadrilaterals.

The complete paragraph is shown below:

<em>Since </em><u><em>AD</em></u><em> is parallel to </em><u><em>BC</em></u><em>, alternate interior angles. </em>

<u><em>AD</em></u><em> and </em><u><em>BC</em></u><em> are congruent. </em>

<em>AC is congruent to </em><u><em>AC</em></u><em> since segments are congruent to themselves.</em>

<em>Along with the given information that AD is congruent to BC, triangle ADC is congruent to triangle </em><u><em>CBA</em></u><em> by the Side-Angle-Side Triangle Congruence. </em>

<em>Since the triangles are congruent, all pairs of corresponding angles are congruent, so angle DCA is congruent to </em><u><em>angle BAC</em></u><em>.</em>

<em>Since those alternate interior angles are congruent. AB must be parallel to </em><u><em>CD</em></u><em>. </em>

<em>Since we define a parallelogram as a quadrilateral with both pairs of opposite sides parallel, ABCD is a parallelogram.</em>

To learn more on quadrilaterals, we kindly invite to check this verified question: brainly.com/question/25240753

8 0
2 years ago
The product of three integers is -3. Determine all of the possible values for the three factors
ryzh [129]
-3, 1, and 1 maybe? That's my guess.
8 0
3 years ago
6. What percentage of the children in class 5 is a member of a sports club? 3
Juliette [100K]

Answer:

75%

Step-by-step explanation:

Let x be the percentage for sports club members.

x% of 20 = 15

x/100 x 20 = 15

x/5 = 15

x = 75

5 0
3 years ago
What is the simplified version of 3\sqrt{135}
Aleonysh [2.5K]

Answer:

The simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

Step-by-step explanation:

The given expression is

\sqrt[3]{135}

According to the property of radical expression.

\sqrt[n]{x}=(x)^{\frac{1}{n}}

Using this property we get

\sqrt[3]{135}=(135)^{\frac{1}{3}}

\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}      [\because (ab)^x=a^xb^x]

\sqrt[3]{135}=3\times \sqrt[3]{5}     [\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]

\sqrt[3]{135}=3\sqrt[3]{5}

Therefore the simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

7 0
3 years ago
Read 2 more answers
the angle of depression from the top ski lift is 57 degrees if the vertical distance from the top and bottom ot the lift is 1200
dedylja [7]

Answer:

1200

Step-by-step explanation:

ghgvhjhv g fty ftvyuibn

7 0
3 years ago
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