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daser333 [38]
3 years ago
8

Please help du tomorrow

Mathematics
1 answer:
Leokris [45]3 years ago
3 0
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².

To find the perimeter of each, we add the area of all sides.  For the first figure, the missing sides are 1 cm and 6 cm.  To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.

For the second figure, the missing sides are 4 cm and 3 cm.  To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.

For the third figure, the missing sides are 3 cm, 3 cm and 8 cm.  To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.

For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm.  To find the area, we have two squares whose dimensions are 10x10.

For the fifth figure, the missing sides are 3 cm and 9 cm.  To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
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the is 51

Step-by-step explanation:

24 + 32 + -5 is 51

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F(x)=x2-10 and g(x)=11-x find (f-g)(x)(f-g)(10) and (f/g)(x) if they exist
tester [92]

Answer:

(f - g)(x) = x^2 + x-21

(f - g)(10) = 89

(f/g)(x) = \frac{x^2 - 10}{11 - x}

Step-by-step explanation:

Given

f(x) = x^2 - 10

g(x) = 11  - x

Solving (1): (f-g)(x)

(f - g)(x) = f(x) - g(x)

Substitute values for f(x) and g(x)

(f - g)(x) = x^2 - 10 - (11 - x)

Open Bracket

(f - g)(x) = x^2 - 10 - 11 + x

(f - g)(x) = x^2 -21 + x

Reorder

(f - g)(x) = x^2 + x-21

Solving (2): (f-g)(10)

In (1)

(f - g)(x) = x^2 + x-21

So:

(f - g)(10) = 10^2 + 10-21

(f - g)(10) = 100 + 10-21

(f - g)(10) = 89

Solving (3): (f/g)(x)

(f/g)(x) = \frac{f(x)}{g(x)}

Substitute values for f(x) and g(x)

(f/g)(x) = \frac{x^2 - 10}{11 - x}

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