Find a linear function g, in slope intercept form, given g(-2)=-3 and g(2)=1
1 answer:
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The first step to solving this is to use tan(t) = 
to transform this expression.
cos(x) ×
Using cot(t) =
,, transform the expression again.
cos(x) ×
Next you need to write all numerators above the least common denominator (cos(x)sin(x)).
cos(x) ×
Using sin(t)² + cos(t)² = 1,, simplify the expression.
cos(x) ×
Reduce the expression with cos(x).
Lastly,, use
= csc(t) to transform the expression and find your final answer.
csc(x)
This means that the final answer to this expression is csc(x).
Let me know if you have any further questions.
:)
cos(x) ×
Using cot(t) =
cos(x) ×
Next you need to write all numerators above the least common denominator (cos(x)sin(x)).
cos(x) ×
Using sin(t)² + cos(t)² = 1,, simplify the expression.
cos(x) ×
Reduce the expression with cos(x).
Lastly,, use
csc(x)
This means that the final answer to this expression is csc(x).
Let me know if you have any further questions.
:)