Answer:
549
Step-by-step explanation:
<u>G</u><u>iven </u><u>:</u><u>-</u><u> </u>
- A sequence 4 , 9 , 14 , ...
And we need to find out the 110th term . the given sequence is in Arithmetic progression . So the common difference is 9 -4 = 5 . Now using the formula to find out the nth term of AP ,
<u>Using</u><u> </u><u>formula</u><u> </u><u>:</u><u>-</u><u> </u>
T_n = a + ( n -1)d
T_n = 4 + (110-1)5
T_110 = 4 + 109*5
T_110 = 4 + 545
T_110 = 549 .
<u>Hence </u><u>the </u><u>1</u><u>1</u><u>0</u><u> </u><u>th </u><u>term </u><u>is </u><u>5</u><u>4</u><u>9</u><u> </u><u>.</u>
The answer is 2.
Hope this helps! :)
Answer:
far
Step-by-step explanation:
jesus told me and u gotta trust jesus and not ur math teachers logic which is always weird
Answer:
C
Step-by-step explanation:
A. 2*6 = 12 but 24p*2 doesn't equal 24p
B. 3*9 doesn't equal 12, and 3*21p doesn't equal 24p
C. 4*3 equals 12 and4*6p=24p
D. 6*2=12, but 6*3p doesn't equal 24p
I hope this helps!!!
After I looked up some quick information, your car loses 15-25% each year. After 5 years, it goes to only 37%. So, a car that would cost 20000 would be valued at around 7k after 5 years. So, in the first 5 years, it lost 14k. Also, a 1999 Corolla goes for 2.5k, and that's nearly 20 years. So, I'm just going to go with, based off these numbers, probably 25-30 years...if it still works by then.
Also, if you get in a heavy accident the next day, making the car unusable, you rip off your friend. The first scenario only applies if the engine works well and no accidents were on the vehicle either.
