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Inessa [10]
3 years ago
5

Suppose that you construct a histogram and a relative frequency histogram corresponding to a particular frequency table. Identif

y one way the histograms will differ.
Mathematics
2 answers:
Korolek [52]3 years ago
8 0
The histogram will give the actual number of items in each interval. This is called the frequency.

The relative frequency histogram will give the percent of items that are in the interval out of the total possible number.
salantis [7]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that you construct a histogram and a relative frequency histogram corresponding to a particular frequency table.

Histogram is representing actual frequency for a class interval in numbers.

But relative histogram gives the ratio of actual frequency to the sum of frequencies.

Thus histogram gives actual while relative histogram gives ratio.

Histogram figures may be greater than 1, but relative histogram figures are always less than 1.

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64 * 6 = 384

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Point a pq and r are collinear on pr and pq: pr =2/3. P is located on the origin q is located at (x,y) and r is located at (-12,
dybincka [34]

The values of x and y are  8 and 0 respectively.

<em><u>Explanation</u></em>

As 'p' is located at (0,0) and 'r'  is located at (-12,0) , that means both 'p' and 'r' are on the x-axis.  So point 'q' will be also on the x-axis , and 'q' is located at (x,y)

So, the value of y will be 0. That means the co ordinate of point 'q' is (x, 0)

Now, using the Distance formula, length of 'pq' = \sqrt{(x-0)^2 +(0-0)^2}= \sqrt{x^2}= x

and length of  'pr'  = \sqrt{(-12-0)^2+(0-0)^2}= \sqrt{144}=12

Given that,   pq : pr =2/3

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3 years ago
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