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Harlamova29_29 [7]
3 years ago
11

Can someone solve or explain to me how to do this?

Mathematics
1 answer:
Andreyy893 years ago
7 0

Answer:

a) x=5

b) x=6

Step-by-step explanation:

a)

3x+7=180-(10x-22)

3x+7=202-10x

13x=195

x=5

b)

11x-3=4x+39

7x=42

x=6

I am so sorry I forgot what the formula names are but these are the correct solutions. It has been a while since I've done Geometry.

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The length of a rectangle is three more than twice the width. The perimeter is 96. What are the dimensions? ​
SIZIF [17.4K]

Answer:

Width =15

Length =33

Step-by-step explanation:

Take width as x

And length as 2x+3

Perimeter as 96

Formula of the perimeter of a rectangle is 2l+2w

X+×+2×+3+2×+3=96

6x+6=96

6x=96-6

6×=90

X=15

Width =x and x =15 so width =15 while length =33

7 0
4 years ago
Formulating and solving inverse variation functions
andreyandreev [35.5K]

Answer:

See below.

Step-by-step explanation:

A. k = 50 * 3.6 = 180.

B. The equation is y = 180/x.

C. When x = 75, y = 180/75

= 2.4.

D.  Checking C:  2.4 = 180/75 = 2.4. Correct

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%283a%5E2b%29%5E3%7D%7B9%28ab%29%5E4%7D" id="TexFormula1" title="\frac{(3a^2b)^3}{9(
VladimirAG [237]

You first multiply the outside exponents into the numbers in the parentheses.

When you have an exponent being multiplied directly to another exponent, you multiply the exponents together.

For example(because I am a bad explainer):

(x^{2} )^4= x^{2(4)} = x^8

(x^4)^3 = x^{4(3)} = x^{12}


When you divide an exponent by an exponent, you subtract the exponents

For example:

\frac{x^4}{x^1} =x^{4-1}=x^3


When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive

For example:

x^{-3}=\frac{1}{x^3}

\frac{1}{y^{-5}}=\frac{y^5}{1}=y^5



\frac{(3a^2b)^3}{9(ab)^4}

You can think of it like this if you want:

\frac{(3^1a^2b^1)^3}{9(a^1b^1)^4}  Now multiply the outside exponents into the exponents in the parentheses

\frac{3^3a^6b^3}{9(a^4b^4)} =\frac{27a^6b^3}{9(a^4b^4)} Divide 27 and 9

\frac{3a^6b^3}{a^4b^4} =(3)(a^{6-4})(b^{3-4})=(3)(a^2)(b^{-1})=(3)(a^2)(\frac{1}{b^1})=\frac{3a^2}{b}



Your answer is \frac{3a^2}{b}



5 0
3 years ago
PLEASE HELP ME FAST!
choli [55]

Answer:

50% chance

Step-by-step explanation:

There is a 50% chance because there in a 3/6 chance he will pick a number above 2

7 0
4 years ago
A1 be the event that the receiver functions properly throughout the warranty period, A2 be the event that the speakers function
andreyandreev [35.5K]

Answer:

0.7448

Step-by-step explanation:

P(A1) =0.95

P(A2) =0.98

P(A3) =0.8

We have to find P( all three components function properly)=P(A1∩A2∩A3).

We know that the these three events are independent so,

P( all three components function properly)=P(A1∩A2∩A3)=P(A1)*P(A2)*P(A3)

P( all three components function properly)=P(A1∩A2∩A3)=0.95*0.98*0.80

P( all three components function properly)=P(A1∩A2∩A3)=0.7448

6 0
4 years ago
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