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3 years ago

Can someone solve or explain to me how to do this?

Mathematics

1 answer:

Andreyy893 years ago

7 0

Answer:

a) x=5

b) x=6

Step-by-step explanation:

3x+7=180-(10x-22)

3x+7=202-10x

13x=195

x=5

11x-3=4x+39

7x=42

x=6

I am so sorry I forgot what the formula names are but these are the correct solutions. It has been a while since I've done Geometry.

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WARRIOR [948]

Answer:

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3 years ago

Find the slope between these two points: (2,-1) and (10,-13)

yuradex [85]

Answer:

-3/2

Step-by-step explanation:

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3 years ago

Read 2 more answers

Anne has 12 coins in her pocket consisting of nickels and dimes only. the total value of the coins is $0.95. how many nickels an

Pie

You have to use a system. the first would be x + y = 12 since she has 12 coins. the other equation would be 0.05x + 0.1y = 0.95 (an easier way is 5x + 10y = 95 if you clear it). now you just solve using substitution or elimination.

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4 years ago

Show that every perfect square is congruent to 0, 1, or 4 modulo 8

Keith_Richards [23]

You want to prove that

$n^2\equiv k\mod8,k\in\{0,1,4\}$

for (presumably) all integers $n\ge1$ .

Let's consider some sub-cases.

Suppose $n=2\ell-1$ is odd. Then

$n^2=(2\ell-1)^2=4\ell^2-4\ell+1$

If $\ell$ is even, then so is $\ell^2-\ell$ , which means you can write $4\ell^2-4\ell=8m$ for some integer $m$ , and this reduces to $n^2\equiv1\mod8$ .

If $\ell$ is odd, the same thing happens; you get that $\ell^2-\ell$ is still even, so $4\ell^2-4\ell\equiv0\mod8$ and you're left again with $n^2\equiv1\mod8$ .

Now assume $n=2\ell$ is even. Then $n^2=4\ell^2$ . If $\ell=2j$ is even, then you will always be able to write

$n^2=(2\ell)^2=4\ell^2=4(2j)^2=8\times2j^2\equiv0\mod8$

Meanwhile, if $\ell=2j-1$ is odd, then

$n^2=4\ell^2=4(2j-1)^2=16j^2-16j+4\equiv4\mod8$

So you conclude that

$n^2\equiv\begin{cases}0\mod8&\text{for }n\in\{4,8,12,16,\ldots\}\\1\mod8&\text{for }n\in\{1,3,5,7,\ldots\}\\4\mod8&\text{for }n\in\{2,6,10,14,\ldots\}\end{cases}$

5 0

3 years ago

Write the slope intercept form of the equation of the line through the given point with the given slope

aleksandrvk [35]

Given that,

Point = (-5,3)

Slope, m = -3/5

To find,

The slope intercept form of the equation of the line.

Solution,

The general form of equation is :

y = mx +b

We have, x = -5, y = 3

So,

$3=\dfrac{-3}{5}(-5)+b\\\\3=-3+b\\\\b = 6$

The equation is :

$y=\dfrac{-3}{5}x+6$

Hence, the required equation is $y=\dfrac{-3}{5}x+6$ .

5 0

3 years ago