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3 years ago

Write the prime factorization of using exponents.

Mathematics

1 answer:

kozerog [31]3 years ago

3 0

Answer: 26∗34 2 6 ∗ 3 4

Step-by-step explanation:

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The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum

wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information: $P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000$ , where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

$\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2$

Equating it to zero we get,

$x^2 + 36x - 6400 = 0$

We use the quadratic formula to find the values of x:

$x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ , where a, b and c are coefficients of $x^2, x^1 , x^0$ respectively.

Putting these value we get x = -100, 64

Now, again differentiating

$\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x$

At x = 64, $\displaystyle\frac{d^2(P(x))}{dx^2} < 0$

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0

3 years ago

Mario invests £2000 for 3 years at 5% per annum compound interest. Calculate the value of the investment at the end of 3 years.

Delicious77 [7]

Answer:

$2315.25

Step-by-step explanation:

Given data

Principal= £2000

Time= 3 years

Rate= 5%

The compound interest expression is

A= P(1+r)^t

substitute

A= 2000(1+0.05)^3

A= 2000(1.05)^3

A= 2000*1.157625

A= 2315.25

Hence the Amount is $2315.25

7 0

3 years ago

Please help me babes!!

abruzzese [7]

The correct answer would be C) CBA-EFD

6 0

3 years ago

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Please help someone

Romashka-Z-Leto [24]

Answer:

(-2, ∞)

Step-by-step explanation:

A function is "increasing" when its graph goes up to the right, the slope is positive. At a turning point (maximum or minimum), the function is neither increasing nor decreasing.

<h3>Increasing interval</h3>

The graph has a minimum at x = -2. To the left of that point, the graph goes up to the left, which is the same as down to the right (decreasing).

To the right of x = -2, the graph goes up to the right (increasing). It continues to increase for all values of x > 2. The interval where the function is increasing is said to be ...

-2 < x < ∞

The lack of "or equal to" tells you the interval is "open" and is delimited by parentheses in interval notation:

increasing; (-2, ∞)

6 0

1 year ago

Justin's pays is represented by this line graph.

Mashutka [201]

Answer:

He is been paid $7 per hour

Step-by-step explanation:

140dollars/ 20 hours

7 0

2 years ago

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