All categories

2 years ago

Which unit would be best for measuring the weight of a boat

1 answer:

8 0

Answer: LBS would be a good unit for measuring the weight of a boat, because lbs is a lot more understandable in contrast to kg etc.

***If you found my answer helpful, please give me the brainliest. :) ***

You might be interested in

The table shows the values of different measurements in the metric system.

Lunna [17]

A micrometer has a power of $10^{-6}$

A millimeter has a power of x $10^{-3}$

A nanometer has a power of $10^{-12}$

A picometer has a power of $10^{-12}$

We are to write the numbers in standard form.

Standard form is a way of writing simplifying numbers and expressing numbers to a power of 10.

For example, to express 1000 in standard form, count the number of digits after the first number. There are 3 zeros. 3 would be the power of the number. So, 1000 in standard form is 1 x 10³

To express a decimal in standard form, count the numbers of zeros and the first non-zero digit The negative of the number would be the power.

For example, 0.001 is standard form is 1 x $10^{-3}$

A micrometer has 6 digits after the decimal point , it power would be x $10^{-6}$

A millimeter has 3 digits after the decimal point, its power would be x $10^{-3}$

A nanometer has 9 digits after the decimal point, its power would be x $10^{-12}$

A picometer has 12 digits after the decimal point, its power would be x $10^{-12}$

To learn more about standard form, please check: brainly.com/question/23123973?referrer=searchResults

4 0

2 years ago

Find the value of x and explain how you found it. Make sure to cite the problem and share what you see before you explain your s

klemol [59]

Answer:

THE VALUE OF X = 3 .

Step-by-step explanation:

From the Δ RQP and Δ TSP ;

⇒ ∠ TPS = ∠ RPQ ( since both are common angle )

⇒ RQ ≈ TS ( parallel lines )

⇒ ∠ PRQ = ∠ PST ( Corresponding angle )

∴ Δ RQP ≅ Δ TSP ( BY ASA RULE )

Now ,

$\frac{RP}{TP} = \frac{QP}{PS}$

$\frac{9 + X}{9} = \frac{6 + 2}{6}$

⇒ X = 3

6 0

3 years ago

Three locations are marked next to a river. Points B and C are on the same side of the river, and point A is on the other side o

nlexa [21]

Answer:

74.31353

=74 m

Step-by-step explanation:

given that three locations are marked next to a river. Points B and C are on the same side of the river, and point A is on the other side of the river. To find the distance AB across a river, a distance BC of 241 meters is laid off on one side of the river. It is found that the angle at point B is 108.6° and the angle at point C is 14.9°.

we have information about triangle ABC as side BC =241, Angle B = 108.6 and angle C = 14.9 degrees.

Hence this is an obtuse scalene triangle.

Angle ∠A = 56.5° (III angle)

Using sine formula we get

$\frac{AB}{sin 14.6} =\frac{BC}{sin 56.5} \\AB = 74.31353$

So distance AB is 74 metres.

5 0

2 years ago

Yall good at slope? if so, i need help

atroni [7]

Answer:

Undefined

Step-by-step explanation:

It's undefined since slope is based on the x coordinate, and since it doesn't change here there is none. It's also undefined because the line is vertical. Hope this helps :)

6 0

2 years ago

Read 2 more answers

Can someone plz help me with math?? theres only 3 parts!!!

vovikov84 [41]

To find the volume of each prism, you will multiply the length by the width by the height.

V = lwh
3 3/4 x 3 x 3 1/4
V = 36 9/16 cubic feet

V = lwh
1/4 x 1/4 x 1/4
V= 1/64 cubic feet

Both boxes are similar in that they can be described as a rectangular prism.

They are different because one prism has congruent edges, so we call it a cube. The other one has varying side lengths, therefore it is only a rectangular prism.

3 0

3 years ago

Read 2 more answers