9514 1404 393
Answer:
- no
- yes
Step-by-step explanation:
Put the values of x and y in the equation and see if it is true.
1. 2 = 2×0 . . . . False (not a solution)
2. 12 = 6×2 . . . True (is a solution)
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
Learn more about spring constant:
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Because they dont have variables
Answer:
0.42
Step-by-step explanation:
Add 9 to 3 to get 12, divide 12 by 100 and add it to 0.3 to get your answer.
In standard form the equation is 3x + -4y = -12
