C=(1/4)*circumference
Area=pq+3.142r^2
60*3.142=pq+3.142p^2
q=((1/4)*2p*3.142)+2*3.142
q=1.571p+6.284
188.52=1.571p^2+6.284p+3.142p^2
188.52=4.713p^2+6.284p
188520=4713p^2+6284p
The shapes below that have a constant cross-section between a pair of faces are cylinder, cube, sphere, hexagonal, and prism.
<h3>What is the definition of geometry?</h3>
It is concerned with the geometry, region, and density of various 2D and 3D shapes.
A cylinder is a closed solid with two parallel circular bases and a curving surface connecting them.
The shapes have a constant cross-section between a pair of faces like a cylinder.
Hence,cylinder, cube, sphere, hexagonal, and prism are the forms below that have a constant cross-section between a pair of faces.
To learn more about geometry, refer to brainly.com/question/7558603.
#SPJ1
P(t)=500(1+4t/(50+t^2 ))
P'(t) = 500 [(50+t^2).4 - 4t.2t]/(50+t^2)^2
by the quotient rule
500 (-4t^2 + 200)/(t^2 + 50)^2
Hence
P'(2) = 500 . (-16 + 200)/54^2 ~= 31.6
<span>No, because postulates are assumptions. Some true, some not. So it can't be used to prove it</span>
