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Airida [17]
3 years ago
15

A sprinkler that sprays water in a circular area can spray up to a radius of 22 ft.

Mathematics
2 answers:
kifflom [539]3 years ago
8 0
<span>1520.5</span>^2 feet is the answer
Tomtit [17]3 years ago
5 0

Answer:

<h2>1520.5^2  ft</h2>

Step-by-step explanation:

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A software company is hiring some programmers to add to its development team. A junior programmer salary is $48,000 and a senior
emmainna [20.7K]

Answer:

48,000x + 86,000y \leq 1,200,000

Step-by-step explanation:

x is the number of junior programmers.

Each junior programmers costs $48,000.

So, the cost of x junior programmers is

48,000x

y is the number of senior programmers

Each senior programmer costs $86,000

So the cost of y seniors programmers is

86,000y

The total cost for x junior programmers and y seniors programmers is

48,000x + 86,000y

To keep costs down, the total spending on these new positions must be under $1,200,000 annually.

So the inequality is:

48,000x + 86,000y \leq 1,200,000

8 0
3 years ago
Write the slope-intercept form of the equation of the line through the given point with the given slope.
SIZIF [17.4K]
Slope itnercept is y=mx+b

ok, let's start with point slope form
y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m
so given point (-3,4) and slope -3/4
y-4=-3/4(x-(-3))
y-4=-3/4(x+3)
distribute to solve for y
y-4=(-3/4)x-9/4
add 4 to both sides
y=(-3/4)x-9/4+4
y=(-3/4)x-9/4+16/4
y=(-3/4)x+7/4
5 0
3 years ago
A concentric-tube heat exchanger cools hot water owing at 1 kg/s from 80C to 30C. It uses air owing at 5 kg/s to perform this co
nordsb [41]

Answer:

The log-mean-temperature-difference is 24.03⁰C

Step-by-step explanation:

First we need to know if the heat exchanger is in parallel flow or counter-flow. However, counter flow arrangement is best used to recover heat.

L.M.T.D for counter flow is given as;

L.M.T.D =\frac{(T_h_f_1 -T_c_f_2)-(T_h_f_2 -T_c_f_1)}{2.3log[\frac{T_h_f_1 -T_c_f_2}{T_h_f_2 -T_c_f_1}]}

where;

Thf₁ is the initial temperature of the hot fluid = 80°C

Tcf₂ is the final temperature of the cold fluid = 51.5°C

Thf₁ - Tcf₂ = 80 - 51.5 = 28.5⁰C

Thf₂ is the final temperature of the hot fluid = 30°C

Tcf₁ is the initial temperature of the cold fluid = 10°C

Thf₂ - Tcf₁ = 30 - 10 = 20⁰C

L.M.T.D = \frac{28.5 -20}{2.3Log[\frac{28.5}{20}]} \\\\L.M.T.D = \frac{8.5}{0.3538} =24.03^oC

Therefore, the log-mean-temperature-difference is 24.03⁰C

3 0
2 years ago
Read 2 more answers
Group the first two terms by underline the first two terms 16x^3-4x^2-4x+1
Daniel [21]

Answer:

Terms are the things that are separated by a (+) or a (-).

Step-by-step explanation:

<u>16x^3</u> - <u>4x^2</u> -4x+1

I don't think I'm right...

7 0
2 years ago
What are the Terms for 8x+6
densk [106]

Answer:Simplifying

8x + 6

Reorder the terms:

6 + 8x

Factor out the Greatest Common Factor (GCF), '2'.

2(3 + 4x)

Final result:

2(3 + 4x)

6 0
3 years ago
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