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ikadub [295]
3 years ago
9

Helpppppppppppppppppppppppppppppp

Mathematics
2 answers:
shutvik [7]3 years ago
6 0

helpppppppppppppppppppppppppppppp What help

hoa [83]3 years ago
4 0

we need a picture or something !! :)
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0.2%

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\begin{array}{cccc}&P&N&T\\P&TP&0.9&90\\N&FP&9.8&10\end{array}

We have, FN = 0.9, TN = 9.8, TP = 90 - 0.9 = 89.1, FP = 10 - 9.8 = 0.2

FNR = FN/(FN + TP) = 0.9/(0.9 + 89.1) = 0.01

FPR = 0.2/(0.2 + 9.8) = 0.02

TPR = 89.1/(89.1 + 0.9) = 0.99

TNR = 9.8/(9.8 + 0.2) = 0.98

P(C/A) = TPR × P(C)/((TPR × P(C) + FPR×(1 - P(C)))

Where;

P(C/A) = The probability that a correct weight package is accepted

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The probability that a correctly weighed package is rejected, P(C/R), is given as follows;

P(C/R) = 1 - P(C/A)

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The probability that a correctly weighed package is rejected, P(C/R) ≈ 0.2%

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