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satela [25.4K]
3 years ago
5

which elements are nonmetals? (A) Silver, Copper, Zinc, Tin (B) Gallium, Zinc, Sulfur, Chlorine (C) Neon,Sulfur, Iodine, Xenon

Chemistry
1 answer:
stealth61 [152]3 years ago
4 0

Answer:

neon sulfur iodine xenon

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NH₄NO₃ → N₂O + 2H₂O When 45.70 g of NH₄NO₃ decomposes, what mass of each product is formed?
Anna007 [38]

Answer: 25.13 g of N_2O  and 20.56 g of H_2O will be produced from 45.70 g of NH_4NO_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} NH_4NO_3=\frac{45.70g}{80.04g/mol}=0.571moles

The balanced chemical equation is:

NH_4NO_3\rightarrow N_2O+2H_2O  

According to stoichiometry :

1 mole of NH_4NO_3 produce = 1 mole of N_2O

Thus 0.571 moles of NH_4NO_3 will require=\frac{1}{1}\times 0.571=0.571moles  of N_2O  

Mass of N_2O=moles\times {\text {Molar mass}}=0.571moles\times 44.01g/mol=25.13g

1 mole of NH_4NO_3 produce = 2 moles of H_2O

Thus 0.571 moles of NH_4NO_3 will require=\frac{2}{1}\times 0.571=1.142moles  of H_2O  

Mass of H_2O=moles\times {\text {Molar mass}}=1.142moles\times 18g/mol=20.56g

Thus 25.13 g of N_2O  and 20.56 g of H_2O will be produced from 45.70 g of NH_4NO_3

5 0
3 years ago
Based on the enthalpy changes given for the reactions, which reactions are endothermic?
aksik [14]

Answer:

the first and last

Explanation:

the enthalpy Change is positive.

please like and Mark as brainliest

6 0
3 years ago
Which substance is an electrolyte?<br><br> (1) O2 <br> (2) Xe <br> (3) C3H8<br> (4) KNO3
defon

(1) O2  Is a Nonelectrolyte: because it does not ionize when dissolved in a solution

(2) Xe Is a Nonelectrolyte: because it does not ionize when dissolved in a solution

(3) C3H8 Is a Nonelectrolyte: because it does not ionize when dissolved in a solution

(4) KNO3 Is an electrolyte: because it ionizes when dissolved in a solution

Electrolytes:

Electrolytes are the substance whose aqueous solution conducts electricity. These are mainly two types:

1. Strong electrolytes

2. Weak electrolytes:

Strong electrolytes:

Strong electrolytes have following properties:

1. They are ionic compounds.

2. They are completely separates into their ions when dissolved in water.

3. In solution form they conduct electricity due to present of ions but in solid form means neutral molecule does not conduct electricity.

Weak electrolytes:

Weak electrolytes are partially ionizes in water.

In general strong electrolytes are strong acid  and  strong base while weak electrolytes are weak acid and weak bases.

Nonelectrolyte:  

The substance which does not ionize when dissolved in a solution is called non-electrolyte. It is a  poor conductor of electricity.

3 0
3 years ago
Read 2 more answers
Calculate Horxn for the following reaction:H3AsO4(aq) + 4 H2(g) --&gt; AsH3(g) + 4 H2O(l)(Hof [AsH3(g)] = 66.4 kJ/mol; Hof [H
Juli2301 [7.4K]

Answer:

The Standard enthalpy of reaction: \Delta H_{r}^{\circ } = (-172.2) \, kJ

Explanation:

Given- Standard Heat of Formation:

\Delta H_{f}^{\circ } [H_{3}AsO_{4}(aq)] = -904.6 kJ/mol

\Delta H_{f}^{\circ } [H_{2}(g)] = 0 kJ/mol,

\Delta H_{f}^{\circ } [AsH_{3}(g)] = +66.4 kJ/mol

\Delta H_{f}^{\circ } [H_{2}O(l)] = -285.8 kJ/mol

   

<u><em>Given chemical reaction:</em></u> H₃AsO₄(aq) + 4H₂(g) → AsH₃(g) + 4H₂O(l)

<em>The standard enthalpy of reaction:</em> \Delta H_{r}^{\circ } = ?

<u><em>To calculate the Standard enthalpy of reaction</em></u> (\Delta H_{r}^{\circ })<em><u>, we use the equation:</u></em>

\Delta H_{r}^{\circ } = \sum \nu .\Delta H_{f}^{\circ }(products)-\sum \nu .\Delta H_{f}^{\circ }(reactants)

\Delta H_{r}^{\circ } = [1 \times \Delta H_{f}^{\circ } [AsH_{3} (g)] + 4 \times \Delta H_{f}^{\circ } [H_{2}O(l)]] - [1 \times \Delta H_{f}^{\circ } [H_{3}AsO_{4}(aq)] + 4 \times \Delta H_{f}^{\circ } [H_{2}(g)]

\Rightarrow \Delta H_{r}^{\circ } = [1 \times (+66.4\,kJ/mol) + 4 \times (-285.8\,kJ/mol) ] - [1 \times (-904.6\,kJ/mol) + 4 \times (0\,kJ/mol)]

\Rightarrow \Delta H_{r}^{\circ } = [-1076.8\, kJ] - [-904.6\,kJ]

\Rightarrow \Delta H_{r}^{\circ } = (-172.2 \, kJ)

<u>Therefore, the Standard enthalpy of reaction:</u> \Delta H_{r}^{\circ } = (-172.2) \, kJ    

5 0
4 years ago
Which molecular formula is also an empirical formula? <br> 1)C6h6<br> 2)h2o2<br> 3) n2h4<br> 4) n2o5
Vikki [24]
The answer is number 4, N2O5.

Because it can't be divided any further since 2 and 5 do not have a common divisor.
8 0
3 years ago
Read 2 more answers
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