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Verizon [17]
3 years ago
9

Answer ASAP 50 pts

Chemistry
2 answers:
Oduvanchick [21]3 years ago
8 0

Answer:

Loss of reactants through transfer

Explanation:

Reactants can be lost a little when being transferred by human error

Sonja [21]3 years ago
4 0

Percent yield is the ratio between actual and theoretical yield multiplied by 100%. The higher the actual yield the higher is the percent yield. In the percent yield there is always a limiting reagent that creates the difference between what is obtained and what is calculated. Percent yield can never exceed 100% if that happens it means that there was some error in the theoretical yield calculation.

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Please help me I will give a brainleist​
Korvikt [17]
When the dew point temperature and air temperature are equal, the air is said to be saturated. Dew point temperature is NEVER GREATER than the air temperature. Therefore, if the air cools, moisture must be removed from the air and this is accomplished through condensation.
7 0
3 years ago
HELP I DONT KNOW HOW TO DO THIS !!
BlackZzzverrR [31]

Answer:

you divide 71.5 by 2

Explanation:

it's may look intimidating but the question is actually really simple.

5 0
2 years ago
2) Calculate the mass(g) of the following substances:<br> b) 0.119 mole MgCl2
VARVARA [1.3K]

Answer:

MgCl2 = 24 + 2(35.5)

= 95

mass of substance = mol × molar mass

= 0.119 × 95

= 11.305 g

4 0
3 years ago
Someone help please this is due today!!?
maria [59]

Answer:

I think beaker three will take longer to boil since there is more water present,compared to the other beakers

3 0
3 years ago
What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)
Genrish500 [490]

Answer:

34.28 L ( 1.5*22.4 L)

Explanation:

Calculation of the moles of aluminum as:-

Mass = 55 g

Molar mass of aluminum = 26.981539 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{55\ g}{26.981539\ g/mol}

Moles= 2.0384\ mol

According to the reaction:-

4Al+3O_2\rightarrow 2Al_2O_3

4 moles of aluminum react with 3 moles of oxygen gas

1 mole of aluminum react with \frac{3}{4} moles of oxygen gas

2.0384 moles of aluminum react with \frac{3}{4}\times 2.0384 moles of oxygen gas

Moles of oxygen gas = 1.5288 moles

At STP,  

Pressure = 1 atm  

Temperature = 273.15 K

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 1.5288 mol × 0.0821 L.atm/K.mol × 273.15 K

⇒V = 34.28 L ( 1.5*22.4 L)

7 0
3 years ago
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