For reaction a, the mole number of gas increase from 2 to 4. So the entropy will increase, ΔS>0. For b, the gas will change to solid, so the entropy decrease, ΔS<0.
Answer:
E = 15×10⁻²⁹ J
Explanation:
Given data:
Frequency of photon = 2.2× 10⁷ Hz
Energy of photon = ?
Solution:
Formula:
E = h.f
h = 6.63×10⁻³⁴ Js
by putting values,
E = 6.63×10⁻³⁴ Js × 2.2× 10⁷ s⁻¹
E = 14.586 ×10⁻²⁹ J
E = 15×10⁻²⁹ J
The energy of photon is 15×10⁻²⁹ J.
For bleaching a stain, there will be an identifiable odor and it will easily absorb colors and/or stains. Burning a match also has odor involved, but the smoke that is released is from a hot fire that is chemically produced by the formula to make the tip of the match.
Answer
Explanation:O2 = 1.7×10-3M;
N2 = 6.4×10-3M;
NO = 1.1 10-5M.
If i had to answer i would choose a hope this helps
