Since v=4+2t its linear equation in the graph is a straight line. Put t=0,1,2.....give value of v and draw it. For example, if t=-2, v= 0 so the point on XOY axes is A(-2, 0). I hope that this is the answer that you were looking for and it has helped you.
Answer:
The perimeter of the other polygon is ![34\ m](https://tex.z-dn.net/?f=34%5C%20m)
Step-by-step explanation:
we know that
If two figures are similar, then the ratios of its perimeter is equal to the scale factor
Let
z---> the scale factor
x----> the perimeter of the other polygon
y----> the perimeter of the larger polygon
so
![z=\frac{x}{y}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx%7D%7By%7D)
we have
![z=\frac{2}{5}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B2%7D%7B5%7D)
![y=85\ m](https://tex.z-dn.net/?f=y%3D85%5C%20m)
substitute and solve for x
![y=85*(2/5)=34\ m](https://tex.z-dn.net/?f=y%3D85%2A%282%2F5%29%3D34%5C%20m)
The expression that is equivalent to
is
.
Given trigonometric expression is:
![Cos(\frac{\pi }{2}+r )](https://tex.z-dn.net/?f=Cos%28%5Cfrac%7B%5Cpi%20%7D%7B2%7D%2Br%20%29)
<h3>What is the
value of
![Cos(\frac{\pi }{2}+\theta )](https://tex.z-dn.net/?f=Cos%28%5Cfrac%7B%5Cpi%20%7D%7B2%7D%2B%5Ctheta%20%29)
?</h3>
The value of
is
because
lies in the second quadrant and the cosine function is negative in the second quadrant.
So, ![Cos(\frac{\pi }{2}+r )= -Sin r](https://tex.z-dn.net/?f=Cos%28%5Cfrac%7B%5Cpi%20%7D%7B2%7D%2Br%20%29%3D%20-Sin%20r)
The range of sine and cosine functions is the same i.e. [-1,1].
Both the functions are periodic functions with periods 2π.
Hence, the expression that is equivalent to
is
.
To get more about trigonometric functions visit:
brainly.com/question/2193113
Answer:
(x - 3) (x - 9) thus D:)
Step-by-step explanation:
Factor the following:
x^2 - 12 x + 27
The factors of 27 that sum to -12 are -3 and -9. So, x^2 - 12 x + 27 = (x - 3) (x - 9):
Answer: (x - 3) (x - 9)