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Aliun [14]
3 years ago
6

SOMEONE HELP ME PLEASE

Mathematics
2 answers:
faust18 [17]3 years ago
5 0

Answer:

The answer is either 1, 3, or 5

Step-by-step explanation:

There are 6 sides on a singular die and the die is rolled twice the first time it rolls onto 4 and the second onto an odd number. The only odd numbers on a 6 sided die are 1, 3, and 5.

pychu [463]3 years ago
4 0

9514 1404 393

Answer:

  1/12

Step-by-step explanation:

The probability of any given outcome is the ratio of the number of ways that outcome can happen to the total number of outcomes.

  P(4) = 1/6 . . . . . roll = 4 is one of 6 possible outcomes

  P(odd) = 3/6 = 1/2 . . . . . of the 6 possible outcomes, 3 are odd

__

The two rolls of the die are presumed to be independent, so the probability of the two outcomes is the product of their individual probabilities.

  P(4 & odd) = (1/6)(1/2) = 1/12

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Answer:

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Step-by-step explanation:

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# if you need any queshtions aswered speedly hit me up and I got you

7 0
3 years ago
1.06 SINUSOIDAL GRAPH VERTICAL SHIFT <br> What is the period of the function f(x)=cos10x
stealth61 [152]
I got that question and the answer C
5 0
3 years ago
Read 2 more answers
Laina ordered six pizzas for her slumber party. This picture shows how much was left of each pizza the next morning. What
tensa zangetsu [6.8K]

Answer:

theres no picture therefore there is no answer to the question

8 0
3 years ago
How many five-card hands (drawn from a standard deck) contain exactly three fives? (A five-card hand is any set of five differen
VashaNatasha [74]

Answer:

4512.

Step-by-step explanation:

We are asked to find the number of five-card hands (drawn from a standard deck) that contain exactly three fives.

The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4

48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128

We can choose exactly three fives from five-card hands in 4C3*48C3 ways.

4C3*48C3=4*1128=4512

Therefore, 4512 five card hands contain exactly three fives.

4 0
4 years ago
What is the exact volume of a cylinder with a base height of 30, and a radius of 13
Tcecarenko [31]
Volume of a cylinder is \pir^{2}h. This is basically the area of a circle multiplied by the height. You can think of it as congruent circles being stacked on top of each other to create a cylinder. With the given information, all we have to do is substitute the values into the variables

V = \pir^{2}h.
V = \pi(13)^{2}x30
V = \pi x 169 x 30 = \pi 5070

Hope this helps! 
(btw if it asks for "exact" anything, leave the pi. Pi is the ratio of the circumference to its diameter, so not every circle will have a pi of 3.14.)
3 0
4 years ago
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