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3 years ago

13 ➗ 16 equals what? please show me in long divison

1 answer:

3 0

Hi , so we have 13 and 16
16 is bigger than 13 , so we add a 0 to 13.
Now we have 130 divided by 16 , our answer is going to be a decimal because the number 0 was added to the number 13.
We have to find a number that times 16 equals to 130 or a number that is the closest one .
16 times 8 equals to 128 , so 8 is the number that goes after the decimal , then we just keep going.
The final answer is .8125

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Through (2,2) slope 3/2

Mrac [35]

Answer:

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Step-by-step explanation:

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3 years ago

How many solutions are there to the equation below 9x + 27 = 9( x + 2 ) + 9

Nataly [62]

Let's solve the equation:

9x+27 = 9(x+2)+9 ← Distribute 9 to the x and 2

9x+27 = 9x+18+9 ← Combine like terms

9x+27 = 9x + 27 ← Subtract 27 from both sides

9x = 9x

Infinitely many solutions would be correct because no matter what x is, it will always equal each other the both sides of the equation because it is 9 times x on both sides.

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3 years ago

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How do you solve a unite rate

Lera25 [3.4K]

Answer:

To find the unit rate, divide the numerator and denominator of the given rate by the denominator of the given rate.

Step-by-step explanation:

As an example, in this case, divide the numerator and denominator of 70/5 by 5, to get 14/1, or 14 students per class, which is the unit rate.

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3 years ago

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I NEED HELP!!! NOW!!!! A shape is picked at random from the group below.

evablogger [386]

Answer:

not picking a circle, not picking a square, and picking a shape that has only straight edges.

Step-by-step explanation:

All of these are 6/8, or 3/4.

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3 years ago

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Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$

Therefore, the equivalent expression after expanding is given as:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

3 0

3 years ago