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d1i1m1o1n [39]
3 years ago
13

Combine like terms to write an equivalent expression for 4y^2+6x-2y^2+12x?

Mathematics
2 answers:
Marina CMI [18]3 years ago
6 0

4y^2+6x-2y^2+12x\\=4y^2-2y^2+6x+12x\\=2y^2+18x

Lena [83]3 years ago
6 0

Answer:

  • 2y^2 + 18x

Step-by-step explanation:

  • 4y^2 + 6x - 2y^2 + 12x =
  • (4y^2 - 2y^2) + (6x + 12x) =
  • 2y^2 + 18x
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X intercept -7 y intercept -5
Fittoniya [83]
The x-intercept of a line is when the y coordinate is equal to 0. So, the x-intercept would be (0,-7).

The y-intercept of a line is when the x coordinate is equal to 0. So the y-intercept would be (-5,0).

To find the equation of a line, you need the slope and the y-intercept.
We already know the y intercept is -5. The equation for a line is:

Y=mx+b

m stands for slope
b stands for the y intercept.

To find the slope, use the equation-

y1-y2
--------
x1-x2

Another way to say that is the change in y over the change in x.

Plug in the the 2 coordinate points you know, which are (-7,0) and (0,-5).

0+5
-------,
-7-0


5/-7.

The slope is 5/-7
The Y intercept is -5

The equation of the line is y= 5/-7x -5

The coordinate point for the x intercept is (-7,0)
The coordinate point for the y intercept is (0,-5)
7 0
4 years ago
Anyone know how to do this???
frosja888 [35]
Assuming the board games are rectangular boards (which most are) you simply multiply the length with the width to get the area.
6 0
4 years ago
Answer of a ²-10a+16-6b-b^2​
german

\quad a^2-10a+16-6b-b^2

$=(a^2-10a)-(b^2+6b) +16$

$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$

$=(a-5)^2-25-(b+3)^2+9+16$

$=(a-5)^2-(b+3)^2$

5 0
4 years ago
What is the completely factored form of 8x^2 -50
dezoksy [38]
<span>8x^2 -50
= 2(4</span><span>x^2 - 25)
= 2(2x + 5)(2x - 5)

hope it helps </span>
4 0
4 years ago
Perform the indicated operation.(3/a+2) + (4/a-5)
kipiarov [429]

Answer:

\frac{7(a-1)}{(a+2)(a-5)}

Step-by-step explanation:

To solve this operation we need to find the common multiple of both denominators and solve for a.

\frac{3}{a+2} + \frac{4}{a-5} =\frac{3(a-5)+4(a+2)}{(a+2)(a-5)} =\frac{3a-15+4a+8}{(a+2)(a-5)} =\frac{7a-7}{(a+2)(a-5)} =\frac{7(a-1)}{(a+2)(a-5)}

Thus, the solution is 7(a -1) / (a+2)(a-5)

8 0
4 years ago
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