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2 years ago

Combine like terms to write an equivalent expression for 4y^2+6x-2y^2+12x?

Mathematics

2 answers:

Marina CMI [18]2 years ago

6 0

$4y^2+6x-2y^2+12x\\=4y^2-2y^2+6x+12x\\=2y^2+18x$

Lena [83]2 years ago

6 0

Answer:

2y^2 + 18x

Step-by-step explanation:

4y^2 + 6x - 2y^2 + 12x =
(4y^2 - 2y^2) + (6x + 12x) =
2y^2 + 18x

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Solve using the quadratic equation. Round your solution to the nearest hundredth of 2x^2-3x+4

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3 years ago

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The product of 12 and k is 84.<br><br> Solve for k.

Mrac [35]

Answer:

The product of 12 and k is 84

According to the given problem, the equation is

$\boxed{12k = 84} \\ k = \frac{84}{12} \\ \boxed{k = 7}$

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2 years ago

Select from the drop-down menu to correctly compare the numbers. 85‾‾‾√ 8.9860...

jeyben [28]

Answer:

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3 years ago

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Your friend says that the absolute value equation |3x+8|−9=−5 has no solution because the constant on the right side of the equa

xenn [34]

$Solution, solve\:for\:x,\:\left|3x+8\right|-9=-5\quad :\quad x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}$

$Steps:$

$\left|3x+8\right|-9=-5$

$\mathrm{Add\:}9\mathrm{\:to\:both\:sides},\\\left|3x+8\right|-9+9=-5+9$

$\mathrm{Simplify},\\\left|3x+8\right|=4$

$|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\3x+8=-4\quad \quad \mathrm{or}\quad \:\quad \:3x+8=4$

$3x+8=-4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=-4-8,\\\mathrm{Simplify},\\3x=-12,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-12}{3},\\\mathrm{Simplify},\\x=-4$

$3x+8=4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=4-8,\\\mathrm{Simplify},\\3x=-4,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-4}{3},\\\mathrm{Simplify},\\x=-\frac{4}{3}$