All categories

2 years ago

Combine like terms to write an equivalent expression for 4y^2+6x-2y^2+12x?

Mathematics

2 answers:

Marina CMI [18]2 years ago

6 0

$4y^2+6x-2y^2+12x\\=4y^2-2y^2+6x+12x\\=2y^2+18x$

Lena [83]2 years ago

6 0

Answer:

2y^2 + 18x

Step-by-step explanation:

4y^2 + 6x - 2y^2 + 12x =
(4y^2 - 2y^2) + (6x + 12x) =
2y^2 + 18x

You might be interested in

(100 points if answered) (attatched screenshot) Algebra II need question 1 and 2

Elanso [62]

Domain: (-♾,2)U(2,♾), {x | x ≠2}
Range: (-♾,3) U(3,♾), {y | y ≠ 3}

Sorry that’s all I can help with

3 0

3 years ago

rewrite f(x)=x^2+8x-20 in the form that would most easily help you identify the zeros of the function

Snowcat [4.5K]

Answer:

f(x) = (x-2) (x+10)

Step-by-step explanation:

f(x)=x^2+8x-20

Factor the right hand side

What 2 numbers multiply to -20 and add to 8

-2 * 10 = -20

-2 + 10 = 8

f(x) = (x-2) (x+10)

Then we can use the zero product property to help us to find the zero's

8 0

3 years ago

Read 2 more answers

Pls help this is pretty urgent

KIM [24]

Answer:

(a) 0

(b) f(x) = g(x)

Step-by-step explanation:

Given rational function:

$f(x)=\dfrac{x^2+2x+1}{x^2-1}$

Part (a)

Factor the numerator and denominator of the given rational function:

$\begin{aligned} \implies f(x) & = \dfrac{x^2+2x+1}{x^2-1} \\\\& = \dfrac{(x+1)^2}{(x+1)(x-1)}\\\\& = \dfrac{x+1}{x-1}\end{aligned}$

Substitute x = -1 to find the limit:

$\displaystyle \lim_{x \to -1}f(x)=\dfrac{-1+1}{-1-1}=\dfrac{0}{-2}=0$

Therefore:

$\displaystyle \lim_{x \to -1}f(x)=0$

Part (b)

From part (a), we can see that the simplified function f(x) is the same as the given function g(x). Therefore, f(x) = g(x).

Part (c)

As x = 1 is approached from the right side of 1, the numerator of the function is positive and approaches 2 whilst the denominator of the function is positive and gets smaller and smaller (approaching zero). Therefore, the quotient approaches infinity.

$\displaystyle \lim_{x \to 1^+} f(x)=\dfrac{\to 2^+}{\to 0^+}=\infty$