Answer:
There is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 1432
p = 23% = 0.23
Alpha, α = 0.05
Number of theft complaints , x = 321
First, we design the null and the alternate hypothesis
This is a one-tailed test.
Formula:
Putting the values, we get,
Now, we calculate the p-value from the table.
P-value = 0.298
Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.
Conclusion:
Thus, there is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.
The radius of a sphere is calculated through the equation,
V = 4πr³ / 3
where r is the radius. Substituting the radius given in the equation,
V = 4π x (3,760.4 miles)³ / 3 = 2.23 x 10^11 miles
Thus, the volume of the planet Venus is calculated to be 2.23 x 10^11 miles, approximately.
The complete question is
Which statement is true about the factorization of 30x² + 40xy + 51y²<span>?
A. The factorization of the polynomial is 10(3x2 + 4xy + 5y2).
B. The polynomial can be rewritten as the product of a trinomial and xy.
C. The greatest common factor of the polynomial is 51x2y2.
D. The polynomial is prime, and the greatest common factor of the terms is 1.
we know that
case A) </span>is not right because 10 is not a common factor of the three terms.
case B) is not right because the original polynomial is already a trinomial
case C) is not right because the terms do not contain 51x^2y^2
<span>case D) is right
because
</span><span>Factors of 30 are-----> 1,2,3,5,6,10,15,30
</span>Factors of 40 are-----> 1,2,4,5,8,10,20,40
Factors of 51 are-----> 1,51
<span>so
</span><span>The "Greatest Common Factor" is the largest of the common factors
</span><span>the GFC is 1
therefore
the answer is the option
</span>D. The polynomial is prime, and the greatest common factor of the terms is 1<span>
</span>
Check the picture below.
now, we have a triangle with all three sides, thus we can use Heron's Area Formula on the triangle.
![\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=10\\ b=26.695\\ c=22\\ s=29.3475 \end{cases} \\\\\\ A=\sqrt{29.3475(29.3475-10)(29.3475-26.695)(29.3475-22)} \\\\\\ A=\sqrt{29.3475(19.3475)(2.6525)(7.3475)}\implies A\approx \sqrt{11066.007} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 105.195~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BHeron%27s%20area%20formula%7D%20%5C%5C%5C%5C%20A%3D%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%5Cqquad%20%5Cbegin%7Bcases%7D%20s%3D%5Cfrac%7Ba%2Bb%2Bc%7D%7B2%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D10%5C%5C%20b%3D26.695%5C%5C%20c%3D22%5C%5C%20s%3D29.3475%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B29.3475%2829.3475-10%29%2829.3475-26.695%29%2829.3475-22%29%7D%20%5C%5C%5C%5C%5C%5C%20A%3D%5Csqrt%7B29.3475%2819.3475%29%282.6525%29%287.3475%29%7D%5Cimplies%20A%5Capprox%20%5Csqrt%7B11066.007%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20A%5Capprox%20105.195~%5Chfill)
Answer: 2 and 3 scoops
Step-by-step explanation:
i guessed :/
