Answer:
a=9 b=18
Step by-step explanation:
First we will find b.
Because there is no 18 in this set and it's an even set of numbers, this would mean that 18 is not present in the set.
The only way for 18 to the be the mean is for b to equal 19. When calculating the average of 17 and 19 your average, or mean, is 18.
a has to be a number ranging from 7-12.
Through trial and error, it can be found that the missing value of a is 9.
Hope this helps!
-MoCKEry
Answer:
DL
Step-by-step explanation:
Answer:
Explanation:
7. f(x) = x^4 + 3x^3 - 6x^2 - 10x + 8
f(2) = 2^4 + 2^3 - 6^2 - 10(2) + 8
f(2) = 16 + 8 - 12 - 20 + 8
f(2) = 0
8. x^2 - 9 = (x - 3)(x + 3)
x ^2 + x - 6 = (x + 3)(x -2)
Thus, the common factor is x + 3
Answer:
n = -5
Step-by-step explanation:
Solve for n:
n + 2 = 4 n + 17
Hint: | Move terms with n to the left hand side.
Subtract 4 n from both sides:
(n - 4 n) + 2 = (4 n - 4 n) + 17
Hint: | Combine like terms in n - 4 n.
n - 4 n = -3 n:
-3 n + 2 = (4 n - 4 n) + 17
Hint: | Look for the difference of two identical terms.
4 n - 4 n = 0:
2 - 3 n = 17
Hint: | Isolate terms with n to the left hand side.
Subtract 2 from both sides:
(2 - 2) - 3 n = 17 - 2
Hint: | Look for the difference of two identical terms.
2 - 2 = 0:
-3 n = 17 - 2
Hint: | Evaluate 17 - 2.
17 - 2 = 15:
-3 n = 15
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides of -3 n = 15 by -3:
(-3 n)/(-3) = 15/(-3)
Hint: | Any nonzero number divided by itself is one.
(-3)/(-3) = 1:
n = 15/(-3)
Hint: | Reduce 15/(-3) to lowest terms. Start by finding the GCD of 15 and -3.
The gcd of 15 and -3 is 3, so 15/(-3) = (3×5)/(3 (-1)) = 3/3×5/(-1) = 5/(-1):
n = 5/(-1)
Hint: | Simplify the sign of 5/(-1).
Multiply numerator and denominator of 5/(-1) by -1:
Answer: n = -5
Answer:
- Multiply 5 by 5 to get your first parameter.
- Multiply 6 by 5 to get the denominator, or your second parameter.
- For the second fraction, , you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.
- The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.
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Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>
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<h3>What have we learned?</h3>
We learned how to efficiently make fractions' deominators match.
Questions related to this topic? Ask me in the comments box, please!