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3 years ago

Graph f(x) = 3[x] +9

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

8 0

Answer:

Step-by-step explanation:

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The area of a rectangle is (x4 4x3 3x2 – 4x – 4), and the length of the rectangle is (x3 5x2 8x 4). if area = length × width, wh

viva [34]

Answer:

Area = x4 + 4x3 + 3x2 - 4x - 4

Length = x3 +5x2 + 8x + 4

Width = Area / Length.

Performing long division with polynomial.

x4 + 4x3 + 3x2 - 4x - 4 / x3 + 5x2 + 8x + 4 = x-1

Width = x-1

Step-by-step explanation:

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3 years ago

Brian earns $11 per hour how many hours will Brian have to work until your earns $143? Plssss help me

Grace [21]

Answer:

13 hours

Step-by-step explanation:

You would divide 143 and 11 to get 13, then you multiply 13 and 11 to check your answer.

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4 years ago

The product of 2 and 14 more than a number

Gelneren [198K]

Answer:

Step-by-step explanation:

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3 years ago

How do you write 23.75 as a mixed number

creativ13 [48]

23 3/4. because if it was 0.25, then you know that it is a quarter, 0.50 is half, therefore 0.75 is three quarters

8 0

3 years ago

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Which expressions simplify to 0? Check all that apply. 8g – 8g, (–2g) – 2g, 5g + (–5g), One-half g + one-half, g Negative two-th

victus00 [196]

We have been given 4 expressions. We are asked to choose the expressions, which simplifies to 0.

Let us check our given choices one by one.

1. $8g-8g$

$8(g-g)$

$8(0)=0$

When we will subtract 8g from 8g, we will get 0. Therefore, expression $8g-8g$ simplifies to 0.

2. $(-2g)-2g$

Let us remove parenthesis.

$-2g-2g$

Upon combining like terms, we will get:

$-4g$

Since $(-2g)-2g$ simplifies to $-4g$ , therefore, expression $-2g-2g$ is not a correct choice.

3. $5g+(-5g)$

Let us remove parenthesis.

$5g-5g$

Upon combining terms, we will get:

$5g-5g=0$

Since $5g+(-5g)$ simplifies to 0, therefore, expression $5g+(-5g)$ is a correct choice.

4. $\frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g$

Let us combine the terms as:

$\frac{1+1}{2}g-\frac{2}{3}g+\frac{2}{3}g$

$\frac{2}{2}g-\frac{2}{3}g+\frac{2}{3}g$

$g-g(-\frac{2}{3}+\frac{2}{3})$

$g-g(0)$

$g-(0)=g$

Since $\frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g$ simplifies to $g$ , therefore, expression $\frac{1}{2}g+\frac{1}{2}g-\frac{2}{3}g+\frac{2}{3}g$ is not a correct choice.

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4 years ago

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