Explanation:
A system of equations are two or more equations that has to be valid at the same time. It means that the variables of one equation can be substitute in the other equation.
For example we have <span>y=5x−8</span> and we can substitute this value of y in the other equation
<span>4x+3y=33</span>
<span>4x+3<span>(5x−8)</span>=33</span> we can solve now for x
<span>4x+15x−24=33</span>
<span>19x=33+24</span>
<span>19x=57</span>
<span>x=<span>5719</span>=3</span>.
y can be obtained from the first equation
<span>y=5x−8</span>
<span>y=5⋅3−8=15−8=7</span>
Then <span>x=3</span> and <span>y=7</span>.
Answer:
7.72, 7.9, 7.93
Step-by-step explanation:
Since all the number's ones place begins with 7, you would want to use the tenth's place to solve this problem.
You can see that there is 7, 9, and 9 in the tenths place and that already makes 7 the least number.
7.9 is equivalent to 7.90 so we can see that 7.90 is less than 7.93. That makes 7.93 the greatest number and 7.72 the least.
7.72<7.9<7.93
<h2>25% is the correct answer!</h2><h3></h3><h3>1,000 ÷ 4,000 = 0.25</h3><h3>0.25 = 25%</h3><h3></h3>
Answer:
a. x1,x2,x3,x4
b. 20x1 + 24x2 + 28x3
c. x1 +x2 ≥ 25
Step-by-step explanation:
At a time that spans from 1 to 5pm, we have timing as follows:
1pm - 2pm = x1
2pm - 3pm = x2
3pm - 4pm = x3
4pm - 5pm = x4
a. The decision variables are x1, x2, x3, x4 and these are the number of people for each shift.
b. The objective function is the minimum cost which is
20x1 + 24x2 + 28x3
c. The constraints for each has been listed
1 - 2pm, x1 ≥ 20 workers
2 - 3pm, x1 + x2 ≥ 25
3 - 4pm, x2 + x3 ≥ 25
4 - 5pm, x3 ≥ 30
The question asked us to write the one for 2-3pm, which is x1 + x2 ≥ 25
