The value of p if the pair of equations may have one root common is 1.
<h3>What are the
roots of the equation?</h3>
Let the equation be ax² + bx + c = 0.
Then the roots of the equation will be
The equations are given below.
2x² + px - 1 = 0 and 3x² - 2x - 5 = 0
The roots of the equation 3x² - 2x - 5 = 0 will be
3x² - 5x + 3x - 5 = 0
(3x - 5)(x + 1) = 0
x = -1, 5/3
At x = -1, the value of p will be
2(-1)² + p(-1) - 1 = 0
2 - p - 1 = 0
p = 1
The value of p if the pair of equations may have one root common is 1.
More about the roots of the equation link is given below.
brainly.com/question/12029673
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Answer:
~0.16
Step-by-step explanation:
quotient, i believe, is just the answer to a division problem. divide normally and u get 0.1629
Answer:
286 students attended
148 non students attended
Step-by-step explanation:
Given
Solving (a): Number of students
Represent students with S and non students with N
So:
--- (1)
--- (2)
Make N the subject of formula in (1)
Substitute 434 - S for N in (2)
Open Bracket
Collect Like Terms
Divide through by -2
<em>Hence; 286 students attended</em>
Solving (b):
Recall that
<em>148 non students attended</em>
Answer: Its A 9
Step-by-step explanation: LOLLLLL is that rock lee form Naruto :D
Answer:
32
Step-by-step explanation:
f(x)= 3(x-2)² + 5
Let x = -1
f(-1)= 3(-1-2)² + 5
Parentheses first
f(-1) = 3(-3)^2 +5
Exponents
f(-1)= 3*9 + 5
Multiply
f(-1) = 27+5
Add
f(-1) = 32
