The maximum speed of a boat at 30 feet length of water is 0.093 nautical miles/hour or knots.
<u>Step-by-step explanation:</u>
- The equation for the maximum speed, s is given by s²= (16/9)x
- where, x is the length of the water line in feet.
It is given that, the modeled equation s²= (16/9)x is used to find the maximum speed in knots or nautical miles per hour.
The question is asked to find the maximum speed when the length of the water is 30 feet.
Therefore, to find the maximum speed in 30 feet water, the given modeled equation is used. So, substitute the 30 feet in place of x.
<u>Now, calculating the maximum speed :</u>
s² = (16/9)(30)
s² = 480 / 9
s² = 53.3
Taking square root on both sides,
s = √53.3
s = 7.3
The maximum speed of a boat at 30 feet length of water is 7.3 nautical miles/hour or knots.
To answer this, you will use the area of 900 square yards to determine the distances between the bases. Each side of the square is 30 yards, so it will be 30 yards from 1st to home and from 1st to 2nd.
The distance from home to 2nd is a diagonal in the square (the hypotenuse).
You will use the Pythagorean Theorem to find this distance.
a^2 + b^2 = c^2
30^2 + 30 ^2 = c^2
900 + 900 + c^2
1800 = c^2
The square root of 1800 is approximately 42.4 yards.
The ball travels approximately 42.4 yards.
It will be 3 weeks because if you divide 7/2,100 it will become to be 3weeks
Answer: 45/1637
Explanation:
Simplify:
90/3274 = 45/1637
Median is 7, two numbers in the middle is 8 and 6, 8+ 6 = 14 divided by 2 is 7.
Range is largest number minus the smallest number. Largest number is 13 and smallest number is 1. 13-1 equals 12. Range is 12.
12 - 7 = 5 answer is 5
