1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
katen-ka-za [31]
3 years ago
7

Find the surface area of the composite figure

Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0

solution given:

For Cuboid

length[l]=11mm

breadth [b]=9mm

height[h]=6mm

For semi cylinder

height[H]=11mm

radius[r]=\frac{9}{2}=4.5mm

Now

Totalsurface area=2(lb+bh+lh)+½(2πr(r+H))-l*b[/tex]

:2(11*9+9*6+11*6)+22/7*4.5(4.5+11)-11*9

:438+219.2-99

:558.2mm²

Here area of base is subtracted as it is not included.

<u>T</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>s</u><u>u</u><u>r</u><u>f</u><u>a</u><u>c</u><u>e</u><u> </u><u>a</u><u>r</u><u>e</u><u>a</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>o</u><u>m</u><u>p</u><u>o</u><u>s</u><u>i</u><u>t</u><u>e</u><u> </u><u>f</u><u>i</u><u>g</u><u>u</u><u>r</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>:</u><u>5</u><u>5</u><u>8.</u><u>2</u><u>mm²</u><u>.</u>

skad [1K]3 years ago
6 0

Answer:

\displaystyle SA_{Total} = \frac{279 \pi}{4} + 339 \ mm^2

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Factoring

<u>Geometry</u>

Shapes

Congruency

  • Congruent sides and lengths

Radius Formula: \displaystyle r = \frac{d}{2}

  • <em>d</em> is diameter

Surface Area of a Rectangular Prism Formula: SA = 2(wl + hl + hw)

  • <em>w</em> is width
  • <em>l</em> is length
  • <em>h</em> is height

Surface Area of a Cylinder Formula: SA = 2πrh + 2πr²

  • <em>r</em> is radius
  • <em>h</em> is height

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

[Rectangular Prism] <em>w</em> = 9 mm

[Rectangular Prism] <em>l</em> = 11 mm

[Rectangular Prism] <em>h</em> = 6 mm

[Cylinder] <em>d</em> = 9 mm

[Cylinder] <em>h</em> = 11 mm

<u>Step 2: Derive</u>

<em>Modify Surface Area equations and combine</em>

  1. [Surface Area of a Cylinder Formula] Factor:                                                 \displaystyle SA = 2(\pi rh + \pi r^2)
  2. [Surface Area of a Cylinder Formula] Divide by 2 [Semi-Cylinder]:              \displaystyle SA = \pi rh + \pi r^2
  3. [Surface Area of a Semi-Cylinder] Substitute in <em>r</em> [Radius Formula]:             \displaystyle SA = \pi (\frac{d}{2})h + \pi (\frac{d}{2})^2
  4. [Surface Area of a Semi-Cylinder] Evaluate exponents:                                \displaystyle SA = \pi (\frac{d}{2})h + \pi (\frac{d^2}{4})
  5. [Surface Area of a Semi-Cylinder] Multiply:                                                    \displaystyle SA = \frac{\pi dh}{2} + \frac{\pi d^2}{4}
  6. [Surface Area of a Rectangular Prism] Remove top:                                      \displaystyle SA = 2(wh + lh) + lw
  7. Combine Surface Area equations:                                                                  \displaystyle SA_{Total} = \frac{\pi dh}{2} + \frac{\pi d^2}{4} + 2(wh + lh) + lw

<u>Step 3: Find Surface Area</u>

  1. Substitute in variables [Combined Surface Area equation]:                         \displaystyle SA_{Total} = \frac{\pi (9 \ mm)(11 \ mm)}{2} + \frac{\pi (9 \ mm)^2}{4} + 2[(9 \ mm)(6 \ mm) + (11 \ mm)(6 \ mm)] + (11 \ mm)(9 \ mm)
  2. Evaluate exponents:                                                                                         \displaystyle SA_{Total} = \frac{\pi (9 \ mm)(11 \ mm)}{2} + \frac{\pi (81 \ mm^2)}{4} + 2[(9 \ mm)(6 \ mm) + (11 \ mm)(6 \ mm)] + (11 \ mm)(9 \ mm)
  3. Multiply:                                                                                                            \displaystyle SA_{Total} = \frac{99\pi \ mm^2}{2} + \frac{81\pi \ mm^2}{4} + 2[54 \ mm^2 + 66 \ mm^2] + 99 \ mm^2
  4. [Brackets] Add:                                                                                                 \displaystyle SA_{Total} = \frac{99\pi \ mm^2}{2} + \frac{81\pi \ mm^2}{4} + 2[120 \ mm^2] + 99 \ mm^2
  5. Multiply:                                                                                                            \displaystyle SA_{Total} = \frac{99\pi \ mm^2}{2} + \frac{81\pi \ mm^2}{4} + 240 \ mm^2 + 99 \ mm^2
  6. Add:                                                                                                                   \displaystyle SA_{Total} = \frac{279 \pi}{4} + 339 \ mm^2
You might be interested in
What’s the value of the 8 in 281480100
luda_lava [24]

We want to find the value of the 8 in 281,480,100

Let's find the place value of each of the numbers:

2 - hundred millions

8 - ten millions

1 - millions

4 - hundred thousands

8 - ten thousands

0 - thousands

1 - hundreds

0 - tens

0 - ones

I see there are two 8's so I wouldn't be too sure of which value to find, but just in case, we have the chart made above for place values.

There is one 8 at the ten millions value.

There is one 8 at the ten thousands value.

7 0
3 years ago
Read 2 more answers
The access code for a vault consists of four digits. The first digit
Vikki [24]

Answer:

5 * 10 * 10 * 9 = 4500

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which means the sum of w and 3.4 is greater than or equal to 10.5
mr_godi [17]
It states "greater than or equal", therefore, you will have to use a sign which has equal in it.
w + 3.4 ≥ 10.5
5 0
4 years ago
A satellite moves at a speed of 27,950 kilometers per hour. About how much faster is one satellite than the other? Explain how t
Marianna [84]
27,950 k * X Kilometers
_____________________________ All you have to do now is cross multiply
1 hr 1hr
6 0
4 years ago
Me. Ellis is a teacher who tutors after school. Of the students he tutors, 30% need help in computer science and 70% need assist
Anna11 [10]

Answer: There are 82.5% after school students who are enrolled in his classes.

Step-by-step explanation:

Let the total number of students be 100

Percentage of students who need help in computer science = 30%

So, number of students who need help in computer science = 30

Percentage of students who need help in maths = 70%

So, number of students who need assistance in maths  = 70

Of the students who need help,

40% are enrolled in Mr. Ellis's class during the school day,

So, it means 60% are enrolled in his class after the school day.

Number of students who are enrolled in his class after the school day = 60

Number of students who need help in Maths is given by

\frac{70}{100}\times 60=42

Of the students that need help in maths, percent of students are enrolled in his class during the day = 25%

So, number of students who need help in maths and enrolled in his class after school hours

\frac{75}{100}\times 42=31.5

Number of students who need help in computer science and enrolled in his class after school hours

\frac{30}{100}\times 60=18

Therefore, there are 31.5+18=49.5 students who joined his class after school hours,

Percentage of the after students who are enrolled in Mr. Ellis's classes is given by

\frac{49.5}{60}\times 100=82.5\%

Hence, there are 82.5% after school students who are enrolled in his classes.


6 0
4 years ago
Other questions:
  • Ken's Home Supply charges $5 for each foot fencing. Wayne's Warehouse charges $6 for each foot fencing
    10·1 answer
  • What is <br> -3 1/6+ 6 2/3
    5·1 answer
  • “Genetic power is far more potent than atomic power. And it will be in everyone's hands. It will be in kits for backyard gardene
    12·1 answer
  • What planet is 1,800,000,000 miles
    12·1 answer
  • 24 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
    5·1 answer
  • Find the whole amount of 8% of 72 cm
    15·2 answers
  • In a survey of 1000 adults, 34% found they prefer charcoal to gas grills. The 1000 would be considered a:
    6·1 answer
  • Maths help please!!!!!!!!!!!
    13·1 answer
  • 10. Find the missing measure of the missing angle.
    12·2 answers
  • Complete the work to simplify the expression (-2d^5)^4
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!