Can someone please help me

Solnce55 [7]

Answer:

5 to the 15th power.

Step-by-step explanation:

PEMDAS requires us to do parenthesis, then exponents, and then division. Let's do 5³. 5x5x5 is equal to 125. Now, we find 125 to the ninth power. According to my calculations, 125 to the ninth power is equal to 7,450,580,596,923,828,125. Now, we find 5 to the twelfth power, which, according to my calculations, is 244,140,625. Now, we solve. According to my calculations, 7,450,580,596,923,828,125/244,140,625 is equal to 30,517,578,125. 30,517,578,125 is equivalent to 5 to the 15th power. That means that the second option is correct. I hope this helps!

3 0

3 years ago

Expand the binomial<br> <img src="https://tex.z-dn.net/?f=%28x-%5Cfrac%7B2%7D%7B5%7D%29%5E%7B2%7D" id="TexFormula1" title="(x-\f

kkurt [141]

Answer:

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1

If you have the expression:

$(x- \frac{2}{5})^{2}$

You can write the expression it in the following way:

$(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})$

Then, apply the distributive property:

$(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}$

Simplify the expression:

$(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})$

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

$(a-b)^2$

Its expanded form will be:

$(a-b)^2= a^2 -2ab + b^2$

If

$a = x$

$b =\frac{2}{5}$

$(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2$

$(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}$

3 0

3 years ago

Can someone help me solve this?

Sergio [31]

Answer:

m<c = 104°

m<d = 80°

Step-by-step explanation:

Recall: Opposite angles of a cyclic quadrilateral are supplementary. Therefore, their sum equals 180°. Thus:

m<c + 76° = 180°

m<c + 76° - 76° = 180° - 76° (subtraction property of equality)

m<c = 104°

m<d + 100° = 180°

m<d +100° - 100° = 180° - 100° (subtraction property of equality)

m<d = 80°

8 0

3 years ago

I need help with this one asap please and thank you

inna [77]

Answer:

C

Step-by-step explanation:

A

(m² - 3m + 2) / (m² - m)

we see due to a little bit of experience with expressions and multiplications of expressions that

(m² - 3m + 2) = (m - 2)(m - 1)

(m² - m) = m(m - 1)

so,

(m - 2)(m - 1) / (m(m - 1)) = (m - 2) / m

so, that's not it.

B

(m² - 2m + 1) / (m - 1)

we see again

(m² - 2m + 1) = (m - 1)(m - 1)

so,

(m - 1)(m - 1) / (m - 1) = m - 1

so, that's not it.

C

(m² - m - 2) / (m² - 1)

we see again

(m² - m - 2) = (m - 2)(m + 1)

and

(m² - 1) = (m + 1)(m - 1)

so,

(m - 2)(m + 1) / ((m + 1)(m - 1)) = (m - 2) / (m - 1)

yes, that is the solution.

D

(2m² - 4m) / (2(m - 2))

2m(m - 2) / (2(m - 2)) = 2m/2 = m

no, that is not a solution.

8 0

2 years ago

5. What is the slope of the line that passes through (-2, 4) and (7, 1)?

just olya [345]

Answer:

Slope: $-\frac{1}{3}$

Step-by-step explanation:

Step 1: Use slope formula to find the slope

$m = \frac{y2 - y1}{x2- x1}=\frac{4-1}{-2-7}=\frac{3}{-9} =-\frac{1}{3}$

Therefore the slope of a line that passes through (-2, 4) and (7, 1) is $-\frac{1}{3}$

4 0

3 years ago