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Minchanka [31]
3 years ago
9

In a arithmetic sequence with a^1=12, d=3 which term is equal to 159?

Mathematics
2 answers:
const2013 [10]3 years ago
6 0

Answer:

50th term is 159

Step-by-step explanation:

nth term=159

a + (n -1)*d = 159

12 + (n-1)*3= 159

(n - 1)*3 = 159 - 12

(n - 1)*3 = 147

n -1 = 147/3

n - 1 = 49

n = 49 + 1

n= 50

maxonik [38]3 years ago
6 0

Answer: n=50th term

Step-by-step explanation:

An= a1+(n-1)d

An= nth term

A1= first term

N= nth position

D= common difference

An =159

A1= 12

D= 3

N= ?

Substitute the values

An=a1+(n-1)d

159=12+(n-1)3

Collect like terms

159-12=(n-1)3

147=3n-3

147+3=3n

150=3n

N=150/3

N= 50

Therefore 50th term will give 156

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3 years ago
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The rule I'm using is

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4 years ago
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<h3>How to calculate the number of degrees?</h3>

From the information given, it was illustrated that the hour hand of a clock moves −30° every hour.

Therefore, to calculate the degree for a number of hours, we simply have to multiply.

In this case, to get the degree for 2 1/5 hours will be:

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Learn more about time on:

brainly.com/question/26046491

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Step-by-step explanation:

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