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ryzh [129]
3 years ago
10

Can someone help me with this question please. I'll give the brainliest answer to whoever helps me.

Mathematics
1 answer:
Doss [256]3 years ago
5 0

Answer: \sqrt[5]{y}

I realize its probably not the largest readable font. If you are having trouble reading it, it is the square root of y; however, there is a tiny little 5 in the upper left corner to indicate a fifth root. So you would read it out as "the fifth root of y"

The rule I'm using is

x^{1/n} = \sqrt[n]{x}

and the more general rule we could use is

x^{m/n} = \sqrt[n]{x^m}

where m = 1. This rule helps convert from rational exponent form (aka fractional exponents) to radical form.

You might be interested in
Otieno is k years old.He is 5 years older than kidole what will be their age fours to come​
EleoNora [17]

Answer:

Otieno's age in 4 years: k+4

Kidole's age in 4 years: k-1

Step-by-step explanation:

k = Otieno's age

k-5 = Kidole's age

Their ages will increase by 4 years when 4 years pass.

k+4 = Otieno's age in 4 years

k-5+4 = Kidole's age in 4 years

k-1 = Kidole's age in 4 years (after simplifying the expression)

I hope this helps!

6 0
3 years ago
Figure LMNO is a parallelogram.
hodyreva [135]

Answer:

180 degrees

Step-by-step explanation:

Two angles are supplementary when they add up to 180 degrees. Therefore, the sum of Angle L and M's measures is equal to 180°.

6 0
3 years ago
What is the area of the real backyard?
prohojiy [21]
50 meters, because if 4cm is 5 m, then it would be 5( 4cm, which equals 5m) multiplied by 10( 8cm÷4cm= 2.     2×5m= 10). So 5m × 10m = 50m. Hope this helps!
7 0
3 years ago
Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation
just olya [345]

Answer:

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation v(t)= 6t^2-18t+12. We are asked to find the distance that the particle will travel in its first 2 seconds.

s(t)=\int |v(t)|dt

s(t)=\int\limits^2_0 |6t^2-18t+12|dt

Now, we will eliminate the absolute value sign as:

s(t)=\int\limits^1_0 6t^2-18t+12dt+\int\limits^2_1 -6t^2+18t-12dt

s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1

s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1

s(2)=2(1)^3-9(1)^2+12(1)-(2(0)^3-9(0)^2+12(0))-2(2)^3+9(2)^2-12(2)-(-2(1)^3+9(1)^2-12(1))

s(2)=2-9+12-(0)-16+36-24-(-2+9-12)

s(2)=5-(0)-4-(-5)

s(2)=5-4+5

s(2)=6

Therefore, the particle will travel 6 feet in first 2 seconds.

   

 

7 0
3 years ago
Find the area of a rectangle that is 12 cm long and 10 cm wide.
gregori [183]

Answer:

area is length * width

12* 10 = 120cm

the answer is 120cm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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