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ryzh [129]
3 years ago
10

Can someone help me with this question please. I'll give the brainliest answer to whoever helps me.

Mathematics
1 answer:
Doss [256]3 years ago
5 0

Answer: \sqrt[5]{y}

I realize its probably not the largest readable font. If you are having trouble reading it, it is the square root of y; however, there is a tiny little 5 in the upper left corner to indicate a fifth root. So you would read it out as "the fifth root of y"

The rule I'm using is

x^{1/n} = \sqrt[n]{x}

and the more general rule we could use is

x^{m/n} = \sqrt[n]{x^m}

where m = 1. This rule helps convert from rational exponent form (aka fractional exponents) to radical form.

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An author signed copies of her newest book for 57 minutes until the bookstore closed at 5:00 What time did the author begin sign
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Answer:

4:03

Step-by-step explanation:

8 0
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Variables x and y are in direct proportion, and y = 35 when x = 2m. If x = 8m, then y =
Dmitry [639]
Y=140 because U have to go 35 divided by 2 and 8 times 17.5
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Which number is NOT in the solution set of the inequality x>-15?
Ipatiy [6.2K]

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d

Step-by-step explanation:

if x has to be greater than -15 and -20 = x than its not true because -20 isn't greater than -15

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Put these decimals in order starting with the smallest.
iVinArrow [24]

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8.008

8.018

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<em><u>If this helped, please consider picking this answer as the Brainliest Answer. Thank you!</u></em>

3 0
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Someone please help me
allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

4 0
2 years ago
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