The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
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Answer:
A
Step-by-step explanation:
The surface area (A) of a sphere is calculated as
A = 4πr² ← r is the radius
here r = 2, hence
A = 4π × 2² = 4π × 4 = 16π units² → A
Answer:
An odd number is any number than can't be divided by two ! Some examples are 1, 3, and 5.
2 units, 3 units, 6 units
36 units, 1 unit, 1 unit
9 units, 2 units, 2 units
12 units, 3 units, 1 unit
All options stated above would result in a volume of 36 cubic units.
Answer: 30
Step-by-step explanation: To solve this problem, we're going to have to use the Pythagorean theorem...
a² + b² = c²
24² + 18² = c²
576 + 324 = c²
c² = 900
30
30 = c
I hope this helps!
