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BartSMP [9]
3 years ago
14

Alice, Bob, and Carol play a chess tournament. The first game is played between Alice and Bob. The player who sits out a given g

ame plays next the winner of that game. The tournament ends when some player wins two successive games. Let a tournament history be the list of game winners, so for example ACBAA corresponds to the tournament where Alice won games 1, 4, and 5, Caroll won game 2, and Bob won game 3.
Required:
a. Provide a tree-based sequential description of a sample space where the outcomes are the possible tournament histories.
b. We are told that every possible tournament history that consists of k games has probability 1/2k, and that a tournament history consisting of an infinite number of games has zero prob- ability. Demonstrate that this assignment of probabilities defines a legitimate probability law.
c. Assuming the probability law from part (b) to be correct, find the probability that the tournament lasts no more than 5 games, and the probability for each of Alice, Bob, and Caroll winning the tournament.
Mathematics
1 answer:
Andrews [41]3 years ago
3 0

Answer:

I don't know what you think about it is not going to be a great day of school and I don't know what you think about it is not going to be a great day of school

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Mhanifa please help asap! I will mark brainliest!
PIT_PIT [208]

Answer:

(6)

<u>Isosceles trapezoid</u>

  • ∠R and ∠S are supplementary
  • ∠S≅∠T, ∠R≅∠V
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<u>Midsegment is half the sum of the base lengths</u>

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3 years ago
I need help solving this , help !
marin [14]

Answer:

NO

Step-by-step explanation:

Triangle A suggests that the triangle is isosceles.

Isosceles:

Triangle with two congruent angles and sides:

7 , 6 , 7

5 , 4 , 5

9, 12 , 9

Triangle B suggests that the triangle is scalene.

Scalene:

Triangle with no congruent angles or sides:

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If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

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Find the values of A &amp; B so that x^4+x^3+ax+b is divisible by x^2+1
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Answer:

a = 1 b = -1.

Step-by-step explanation:

Suppose the quotient when you divide x^4+x^3+ax+b  by x^2 + 1 is

x^2 + ax + b then expanding we have:

(x^2 + 1)(x^2 + ax + b)

= x^4 + ax^3 + bx^2 + x^2 + ax + b

= x^4 + ax^3 + (b + 1)x^2 + ax + b Comparing this with the original expression:

  x^4 +  x^3  + 0 x^2       + ax + b  Comparing coefficients:

a = 1 and b+ 1 = 0 so b = -1.

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3 years ago
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