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prohojiy [21]
2 years ago
12

The graph of $y = ax^2 + bx + c$ is shown below. Find $a \cdot b \cdot c$. (The distance between the grid lines is one unit.)

Mathematics
1 answer:
Savatey [412]2 years ago
7 0

Answer:

a\cdot b\cdot c=\frac{15}{4}

Step-by-step explanation:

Vertex is the minimum or maximum point of parabola

Vertex of parabola is (h,k)

Therefore, from given graph (-3,-2) is the lowest point.

Vertex of parabola is at (-3,-2).

Standard equation of parabola

y-k=a(x-h)^2

Substitute the values

y-(-2)=a(x-(-3))^2=a(x+3)^2

y+2=a(x+3)^2

(-1,0) lies on the parabola.

Therefore, it satisfied the equation of parabola.

0+2=a(-1+3)^2=4a

a=2/4=1/2

Now, using the value of a

y+2=1/2(x+3)^2=1/2(x^2+6x+9)

y+2=\frac{1}{2}x^2+3x+\frac{9}{2}

y=\frac{1}{2}x^2+3x+\frac{9}{2}-2

y=\frac{1}{2}x^2+3x+\frac{9-4}{2}

y=\frac{1}{2}x^2+3x+\frac{5}{2}

By comparing with

y=ax^2+bx+c

We get

a=\frac{1}{2}, b=3, c=5/2

a\cdot b\cdot c=\frac{1}{2}\times 3\times \frac{5}{2}

a\cdot b\cdot c=\frac{15}{4}

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