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Alekssandra [29.7K]
3 years ago
6

Ir AB - 4x + 9. BC = 5x + 2, and AC - 56. then find the value for x, AB, BC.

Mathematics
2 answers:
tiny-mole [99]3 years ago
6 0

Answer:

A B - 4 x + 9 B C = 5 x + 2 = A = 9 x/ B + 2/ B − 9 C

A C − 56 = A = 9 x /B + 2/ B − 9 C

x=A=9x/B+2x/B-9C

I hope this helps

enyata [817]3 years ago
3 0
Xterm answer is right above me
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When we compare the significance level \alpha=0.1 we see that p_v so we can reject the null hypothesis at 10% of significance. So the  the true mean is difference from 21 at this significance level.

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Data given and notation  

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State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the average age of the evening students is significantly different from 21, the system of hypothesis would be:  

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Alternative hypothesis:\mu \neq 21  

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