Find the area of the figure and choose the appropriate result.

Mathematics

2 answers:

makkiz [27]3 years ago

6 0

Answer:

A- 24m

B- 18.9

C. 11.4

Total- 54.3

Step-by-step explanation:

Naddika [18.5K]3 years ago

4 0

Answer:

41.7 square meters

Step-by-step explanation:

First, rectangle A:

4 x 6 = 24 square meters

Second, rectangle B:

We know the length of this section is 3.5m. For the height/width, we can look at rectangle C. The height of C is 3.8m, and we see the part of C that is NOT part of B is 2m long. So we subtract 2 from 3.8 to find the height of B.

3.8 - 2 = 1.8m

Then, for the area of B:

3.5 x 1.8 = 6.3 square meters

Third, rectangle C:

3 x 3.8 = 11.4 square meters

Add up areas of A, B, C:

24 + 6.3 + 11.4 = 41.7 square meters

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1. Remember what we know about vertical angles and solve for x. (SHOW WORK)

EastWind [94]

Answer:

Ans.1.) X = 7.

Ans.2.a.) AC =JL.

Ans.2.b.) BC = KL.

Step-by-step explanation:

For Question 1.

As we know vertically opposite angles are equal.

$\therefore (x+16)\° = (4x-5)\°\\\therefore (5+16)\° = (4x-x)\°\\ \therefore (3x) = (21)\\\therefore x = 7\\$

For Question 2.a)

$In\ \triangle ABC and \triangle JKL \\AB \cong JK\ \textrm{Given}\\\angle CAB \cong \angle LJK\ \textrm{each measure angle of 90\°}\\AC \cong JL\ \textrm{this is the required information to prove the triangles are congruent by SAS postulate}\\\therefore \triangle ABC \cong \triangle JKL\ \textrm{ By SAS postulate}$

For Question 2.b)

$In\ \triangle ABC and \triangle JKL \\AB \cong JK\ \textrm{Given}\\\angle CAB \cong \angle LJK\ \textrm{each measure angle of 90\°}\\BC \cong KL\ \textrm{this is the required information to prove the triangles are congruent by HL Theorem}\\\therefore \triangle ABC \cong \triangle JKL\ \textrm{ By Hypotenuse length Theorem}$