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Elan Coil [88]
3 years ago
9

Find the area of the figure and choose the appropriate result.

Mathematics
2 answers:
makkiz [27]3 years ago
6 0

Answer:

A- 24m

B- 18.9

C. 11.4

Total- 54.3

Step-by-step explanation:

Naddika [18.5K]3 years ago
4 0

Answer:

41.7 square meters

Step-by-step explanation:

First, rectangle A:

4 x 6 = 24 square meters

Second, rectangle B:

We know the length of this section is 3.5m. For the height/width, we can look at rectangle C. The height of C is 3.8m, and we see the part of C that is NOT part of B is 2m long. So we subtract 2 from 3.8 to find the height of B.

3.8 - 2 = 1.8m

Then, for the area of B:

3.5 x 1.8 = 6.3 square meters

Third, rectangle C:

3 x 3.8 = 11.4 square meters

Add up areas of A, B, C:

24 + 6.3 + 11.4 = 41.7 square meters

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Step-by-step explanation:

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Answer:

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<em><u>Or ;</u></em>

{( \sqrt{ {x}^{ - 3} } )}^{5}  =  {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5}  = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5}  \\  \\  =  ( { \frac{1}{ \sqrt{x}  \sqrt{ {x}^{2} } } })^{5}  =  ({ \frac{1}{ x\sqrt{x} }})^{5}   \\  \\  = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) =  \frac{1}{ {x}^{5}  \times  {x}^{ \frac{1}{2} \times 5 } }  \\  \\  =  \frac{1}{ {x}^{5}  \times  {x}^{ \frac{5}{2} } }  =  \frac{1}{ {x}^{5}  \sqrt{ {x}^{5} } }  \\  \\  =  \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1}  }  }  =  \frac{1}{ {x}^{5}  \sqrt{x}  \sqrt{( { {x}^{2} })^{2} } }  \\  \\  =  \frac{1}{ {x}^{5} {x}^{2}  \sqrt{x}  }  =  \frac{1}{ {x}^{7} \sqrt{x}  }   =  \frac{ \sqrt{x} }{ {x}^{8} }

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2 years ago
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Step-by-step explanation:

5 0
4 years ago
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A pair of coordinate always in a form (x, y)
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Distance = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}
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Distance = \sqrt{78946765}
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Answer:

-1/32.

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= -1/8 * 1/4

= -1/32.

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4 years ago
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