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dalvyx [7]
2 years ago
10

Is the network in d) an Euler circuit? Can this network can be traversed?

Mathematics
1 answer:
beks73 [17]2 years ago
4 0

Answer:

If a graph is an Euler Circuit that mean that it can be traversed and begins and has all even verticies.  This allows you to start and stop at the same verticie.

Step-by-step explanation:

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I'll give brainliest!!! please help!!!
stich3 [128]

Answer:

The answer is the last one. Gravity doesn't have direct contact but it is a force we are all affected by.

Step-by-step explanation:

7 0
2 years ago
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On a 15 hour trip, Rob drove 35% of the time and Mark drove the remainder of the time. How many hours did Mark drive? Explain 9.
Zigmanuir [339]

Answer:

9.75 hours

Step-by-step explanation:

If Rob drove 35% of the time and Mark drove the remainder of the time, the total is 100 %

100-35 = 65

so Mark drove 65% of the time

The total time driven was 15 hours, so we multiply the total time driven by the percentage of time that Mark drove to find the number of hours that Mark drove.

15 * 65%

15*.65

9.75 hours

7 0
3 years ago
Solve for x in the equation x2 + 4x-4=8.
iren [92.7K]

{x}^{2}  + 4x - 4 = 8 \\  =  >  {x}^{2}  + 4x - 4 - 8 = 0 \\  =  >  {x}^{2}  + 4x - 12 = 0 \\  =  >  {x}^{2}  + 6x  - 2x - 12 = 0 \\  =  >  x(x + 6) - 2(x + 6) = 0 \\  =  > (x - 2)(x + 6) = 0 \\  =  > x = 2 \:  \:  \: or \:  \:  \: x =  - 6

<u>Answer</u><u>:</u>

x = -6 or x = 2

Hope you could get an idea from here.

Doubt clarification - use comment section.

7 0
2 years ago
Verify the identity by transforming the left-hand side into the right-hand side.
qaws [65]
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1

Starting with the left:  Note that  cos²θ + </span><span>sin²θ = 1.
In the same way:    </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore                cos²3θ  = 1 - <span>sin²3θ
</span> From the top:  (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ

=  2/<span>sin² 3θ - 1;        But 1/</span><span>sinθ = csc</span><span>θ,  Similarly  </span>1/sin3θ = csc3θ

= 2 *(1/sin<span>3θ)²  - 1</span>
= 2csc²3θ  - 1.        Therefore  LHS = RHS.  QED.

8 0
3 years ago
The lines below are perpendicular. If
RSB [31]

Answer:

Correct answer: s₁ = - 2

Step-by-step explanation:

The relationship between the slope of two lines that are perpendicular is:

s₁ = - 1/s = - 1/(1/2) = - 2

God is with you!!!

5 0
3 years ago
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